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3 years ago

If a student lifts a 25kg of mass at a vertical distance of 1.6 in 2.0seconds what is the force needed to lift the mass?

Physics

1 answer:

Ad libitum [116K]3 years ago

6 0

The force must be at least 245 N

Explanation:

The force needed to lift the mass is at least equal to the force of gravity acting on the mass (also known as the weight of the object).

The weight of an object is given by

$W=mg$

where

m is the mass of the object

$g=9.8 m/s^2$ is the acceleration of gravity at the Earth's surface

The mass of the object in the problem is

m = 25 kg

So, its weight is

$W=(25)(9.8)=245 N$

Therefore, the force to lift the object must be at least equal to 245 N.

Learn more on forces and weight:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

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If a machine exerts a force of 250N on an object and no work is done, what must have occurred?

ss7ja [257]

The object did not move / was kept from moving.

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3 years ago

A straight wire segment 5 m long makes an angle of 30° with a uniform magnetic field of 0.37 T. Find the magnitude of the force

SIZIF [17.4K]

Answer:

The magnitude of the force on the wire is 2.68 N.

Explanation:

Given that,

Length of the wire, L = 5 m

Magnetic field, B = 0.37 T

Angle between wire and the magnetic field, $\theta=30^{\circ}$

Current in the wire, I = 2.9 A

We need to find the magnitude of the force on the wire. The magnetic force in the wire is given by :

$F=BIL\ \sin\theta\\\\F=0.37\ T\times 2.9\ A\times 5\ m\times \ \sin(30)\\\\F=2.68\ N$

So, the magnitude of the force on the wire is 2.68 N. Hence, this is the required solution.

7 0

3 years ago

The potential difference between the plates of a capacitor is 145 V. Midway between the plates, a proton and an electron are rel

aniked [119]

Answer:

= 2.52 x 10^ 6 m/s

Explanation:

The force that acts on charged particles between capacitor plates =

F = (q) (Δv) ÷ d

Here, d = distance between the two plates

q = charge of the charged particle

Δv = voltage

Normally, the force that makes both proton and electron released from rest, giving the charge acceleration is F=m X a. where m= mass and a = acceleration

Poting this equation with the first one, we have:

m X a = (q) (Δv) ÷ d

So, the acceleration of a proton when moving towards a negatively charged plate is

a = (q) (Δv) ÷ (d) (m) {proton}

Likewise, the acceleration of an electron when moving towards a positively charged plate is

a = (q) (Δv) ÷ (d) (m) {electron}

Dividing the proton acceleration formula by the electron acceleration formula we have:

a (proton) / a (electron) = m (proton) / m(electron)

inserting equation of motion to get distance, s

s = ut + 1/2 at^2

recall that electron travel distance, d/2

d/2 = 1/2 at^2

making t the subject of the formula

we have, t =√(d ÷ a(electron))

The distance of proton:

d/2 = ut + 1/2 at^2 [proton}

put d/2 = ut + 1/2 at^2 [proton} into t =√(d ÷ a(electron))

Initial speed, ui = √(d ÷ a(electron)) = (d/2) - (1/2) x (d) (a(proton) + a(electron))

since acceleration wasn't given in the question, lets use mass(elect

ron) ÷ mass(proton) rather than use (a(proton) + a(electron))

Therefore, intial speed= 1/2√((e X Δv) ÷ m(electron)) (1- m(electron)/ m(proton))

Note, e = 1.60 x 10^-19

m(electron) = 9.11 X 10^-31

m(proton) = 1.67 X 10^-27

Input these values into the formula above, initial speed, UI =

= 2.52 x 10^ 6 m/s

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3 years ago

True or False - Auroras appear when the particles collide with atoms and

FromTheMoon [43]

False, because the ions of the solar wind collide with atoms of oxygen and nitrogen from the Earth's atmosphere. The energy released during these collisions causes an aurora.

hope this helps!

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2 years ago

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75% of what number is 27? EXPLAIN

zmey [24]

75 percent (calculated percentage %) of what number equals 27? Answer: 36.

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3 years ago

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