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Talja [164]
3 years ago
14

Perform a theoretical analysis of the rectangular profiled cantilevered beam. Provide a theoretical expression (in symbolic form

) for the surface strain () as a function of the various parameters Cx, L, w , W, E. ? Assuming the metal strip is composed of nominal grade aluminum ( 10% 10 lbfin2 69 × 109 Pa, see TABLE D.9 in the text, substitute and derive a theoretical expression for ?-strain as a function of x, L, and W only, where x and I are in units of millimeters and W'is in units of grams force. Note: 1 gram force the force of gravity on a one gram mass (l g mass) x (acceleration of gravity)-0.0981 N.

Engineering
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

Please kindly endeavour to check the attached file.

Explanation:

Please check the attachment on this answer for clear step by step explanations for the queation

Thanks.

substitute and derive a theoretical expression for ?-strain as a function of x, L, and W only, where x and I are in units of millimeters and W'is in units of grams force. Note: 1 gram force the force of gravity on a one gram mass (l g mass) x (acceleration of gravity)-0.0981 N.

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A bar having a length of 5 in. and cross-sectional area of 0. 7 in.2 is subjected to an axial force of 8000 lb. If the bar stret
andrew11 [14]

The modulus of elasticity is 28.6 X 10³ ksi

<u>Explanation:</u>

Given -

Length, l = 5in

Force, P = 8000lb

Area, A = 0.7in²

δ = 0.002in

Modulus of elasticity, E = ?

We know,

Modulus of elasticity, E = σ / ε

Where,

σ is normal stress

ε is normal strain

Normal stress can be calculated as:

σ = P/A

Where,

P is the force applied

A is the area of cross-section

By plugging in the values, we get

σ = \frac{8000 X 10^-^3}{0.7}

σ = 11.43ksi

To calculate the normal strain we use the formula,

ε = δ / L

By plugging in the values we get,

ε = \frac{0.002}{5}

ε = 0.0004 in/in

Therefore, modulus of elasticity would be:

E = \frac{11.43}{0.004} \\\\E = 28.6 X 10^3 ksi

Thus, modulus of elasticity is 28.6 X 10³ ksi

6 0
3 years ago
A Si sample contains 1016 cm-3 In acceptor atoms and a certain number of shallow donors, the In acceptor level is 0.16 eV above
creativ13 [48]

Answer:

6.5 × 10¹⁵/ cm³

Explanation:

Thinking process:

The relation N_{o} = N_{i} * \frac{E_{f}-E_{i}  }{KT}

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and ni = 1.5 × 10¹⁰

Temperature, T = 300 K

K = 1.38 × 10⁻²³

This generates N₀ = 1.654 × 10¹⁶ per cube

Now, there are 10¹⁶ per cubic centimeter

Hence, N_{d}  = 1.65*10^{16}  - 10^{16} \\           = 6.5 * 10^{15} per cm cube

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Lelu [443]
True I don’t really know.
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3 years ago
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Which type of boot authentication is more secure?
MA_775_DIABLO [31]

The type of boot authentication that is more secure is Unified Extensible Firmware Interface

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Unified Extensible Firmware Interface is a computer software program that work hand in hand with an operating system,  it main function is to stop a computer system from boot with an operating system that is not secured.

For a  computer system to boot successfully it means that the Operating system support the  Unified Extensible Firmware Interface because it secured.

Inconclusion The type of boot authentication that is more secure is Unified Extensible Firmware Interface

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3 years ago
Write an expression that evaluates to true if the value of variable lastName is greater than the string Dexter.
gregori [183]

Answer:

lastName.compareTo("Dexter")>0

Explanation:

The expression that evaluates to true if the value of variable lastName is greater than the string Dexter is; lastName.compareTo("Dexter")>0.

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