Perform a theoretical analysis of the rectangular profiled cantilevered beam. Provide a theoretical expression (in symbolic form
) for the surface strain () as a function of the various parameters Cx, L, w , W, E. ? Assuming the metal strip is composed of nominal grade aluminum ( 10% 10 lbfin2 69 × 109 Pa, see TABLE D.9 in the text, substitute and derive a theoretical expression for ?-strain as a function of x, L, and W only, where x and I are in units of millimeters and W'is in units of grams force. Note: 1 gram force the force of gravity on a one gram mass (l g mass) x (acceleration of gravity)-0.0981 N.
1 answer:
Answer:
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Explanation:
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substitute and derive a theoretical expression for ?-strain as a function of x, L, and W only, where x and I are in units of millimeters and W'is in units of grams force. Note: 1 gram force the force of gravity on a one gram mass (l g mass) x (acceleration of gravity)-0.0981 N.
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Answer:
a)
b)
Explanation:
Previous concepts
The cumulative distribution function (CDF) F(x),"describes the probability that a random variableX with a given probability distribution will be found at a value less than or equal to x".
The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution".
Part a
Let X the random variable of interest. We know on this case that
And we know the probability denisty function for x given by:
In order to find the cdf we need to do the following integral:
Part b
Assuming that , then the density function is given by:
And for this case we want this probability:
And evaluating the integral we got:
Answer:
Enthalpy at outlet=284.44 KJ
Explanation:
We need to Find enthalpy of outlet.
Lets take the outlet mass m and outlet enthalpy h.
So from mass conservation
m=1+1.5+2 Kg/s
m=4.5 Kg/s
Now from energy conservation
By putting the values
So h=284.44 KJ
Answer: Hello the question is incomplete below is the missing part
Question: determine the temperature, in °R, at the exit
answer:
T2= 569.62°R
Explanation:
T1 = 540°R
V2 = 600 ft/s
V1 = 60 ft/s
h1 = 129.0613 ( value gotten from Ideal gas property-air table )
<em>first step : calculate the value of h2 using the equation below </em>
assuming no work is done ( potential energy is ignored )
h2 = [ h1 + ( V2^2 - V1^2 ) / 2 ] * 1 / 32.2 * 1 / 778
∴ h2 = 136.17 Btu/Ibm
From Table A-17
we will apply interpolation
attached below is the remaining part of the solution
Answer:
μ = 0.136
Explanation:
given,
velocity of the car = 20 m/s
radius of the track = 300 m
mass of the car = 2000 kg
centrifugal force
F c = 2666. 67 N
F f= μ N
F f = μ m g
2666.67 = μ × 2000 × 9.8
μ = 0.136
so, the minimum coefficient of friction between road surface and car tyre is equal to μ = 0.136