Perform a theoretical analysis of the rectangular profiled cantilevered beam. Provide a theoretical expression (in symbolic form
) for the surface strain () as a function of the various parameters Cx, L, w , W, E. ? Assuming the metal strip is composed of nominal grade aluminum ( 10% 10 lbfin2 69 × 109 Pa, see TABLE D.9 in the text, substitute and derive a theoretical expression for ?-strain as a function of x, L, and W only, where x and I are in units of millimeters and W'is in units of grams force. Note: 1 gram force the force of gravity on a one gram mass (l g mass) x (acceleration of gravity)-0.0981 N.
1 answer:
Answer:
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Explanation:
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substitute and derive a theoretical expression for ?-strain as a function of x, L, and W only, where x and I are in units of millimeters and W'is in units of grams force. Note: 1 gram force the force of gravity on a one gram mass (l g mass) x (acceleration of gravity)-0.0981 N.
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Answer:
a)Cycle time = 2.37 min
b)Numbers of workers =21
c)Stations on the line =24
Explanation:
Given that
Total work content time(TWC) = 50 min
Production rate Rp= 24 units/hr
manning level will be close =1.5
Line balancing efficiency =0.94
a)
Cycle time
Cycle time = 2.37 min
b)
Numbers of workers ,W
W= 21
Numbers of workers =21
c)
Stations on the line(n)
Lets find service time Ts
Ts = Cycle time - Time for repositioning
Ts = Tc- Tr
Ts= 2.37 - 9/ 60 min
Ts= 2.22 min
We know that efficiency
n=23.94 ⇒n=24
n=24
Stations on the line =24
Answer:
a)31%
b)34MW
Explanation:
A rankine cycle is a generation cycle using water as a working fluid, when heat enters the boiler the water undergoes a series of changes in state and energy until generating power through the turbine.
This cycle is composed of four main components, the boiler, the pump, the turbine and the condenser as shown in the attached image
To solve any problem regarding the rankine cycle, enthalpies in all states must be calculated using the thermodynamic tables and taking into account the following.
• The pressure of state 1 and 4 are equal
• The pressure of state 2 and 3 are equal
• State 1 is superheated steam
• State 2 is in saturation state
• State 3 is saturated liquid at the lowest pressure
• State 4 is equal to state 3 because the work of the pump is negligible.
Once all enthalpies are found, the following equations are used using the first law of thermodynamics
Wout = m (h1-h2)
Qin = m (h1-h4)
Win = m (h4-h3)
Qout = m (h2-h1)
The efficiency is calculated as the power obtained on the heat that enters
Efficiency = Wout / Qin
Efficiency = (h1-h2) / (h1-h4)
For this problem, we will first find the enthalpies in all states
h1=3231kJ/Kg
h2=2310kJ/Kg
h3=h4=272kJ/Kg
A) using the eficiency ecuation
Efficiency = (h1-h2) / (h1-h4)
Efficiency =(3231-2310)/(3231-272)=0.31=<u>31%</u>
b)using ecuation for Wout
Wout = m (h1-h2)
Wout=37(3231-2310)=34077KW=<u>34.077MW</u>
