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2 years ago

Can someone please help me ASAP

Physics

1 answer:

Serggg [28]2 years ago

8 0

Answer:

distance = 6.1022 x10^16[m]

Explanation:

To solve this problem we must use the formula of the average speed which relates distance to time, so we have

v = distance / time

where:

v = velocity = 3 x 10^8 [m/s]

distance = x [meters]

time = 6.45 [light years]

Now we have to convert from light-years to seconds in order to get the distance in meters.

$t = 6.45 [light-years]*365[\frac{days}{1light-year}]*24[\frac{hr}{1day}] *60[\frac{min}{1hr}]*60[\frac{seg}{1min} ] =203407200 [s]$

Now using the formula:

distance = v * time

distance = (3*10^8)*203407200

distance = 6.1022 x10^16[m]

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Consider a large truck and a small car driving up a straight steep hill. The truck is moving at 60 miles per hour and the car at

Oksana_A [137]

Answer:

The correct answer is option A.

Explanation:

Force is defined as push or pull on an object with mass due to which change velocity occurs (acceleration).

$Force=Mass\times Acceleration$

$F=ma$

$a=\frac{dv}{dt}[tex][tex]m\times \frac{dv}{dt}[tex]We are given with large truck and small car at constant speed, which means that acceleration zero.[tex]a=\frac{dv}{dt}=0$ if ,v = constant

Net force on the vehilce

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3 years ago

Who was the scientist who gave us the laws of motion?.

timurjin [86]

Answer:

Isaac Newton

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2 years ago

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The membrane that surrounds a certain type of living cell has a surface area of 4.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A

Nadusha1986 [10]

Answer:

The charge resides on the outer surface = $1.245 \times 10^{-12}$ C

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The capacitance of parallel plate capacitor in free space is given by,

$C = \frac{\epsilon_{o} A }{d}$

Where $\epsilon_{o} =$ permittivity of free space = $8.85 \times 10^{-12}$

The Capacitance of capacitor is increase by $k$ times when it placed in dielectric medium.

$C_{dielectric} = \frac{k \epsilon_{o} A }{d}$

And we know that, $C = \frac{Q}{ \Delta V}$

So charge on the outer surface is given by,

$Q = \frac{k \epsilon A \Delta V }{d}$

$Q = \frac{4.2 \times 4.3 \times 10^{-9} \times 8.85 \times 10^{-12} \times 85.7\times 10^{-3} }{1.1 \times 10^{-8} }$

$Q = 1.245 \times 10^{-12}$

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3 years ago

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3 years ago

-!!! URGENT !!!-

seraphim [82]

Try this option, the answers are marked with colour.

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3 years ago