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2 years ago

Can someone please help me ASAP

Physics

1 answer:

Serggg [28]2 years ago

8 0

Answer:

distance = 6.1022 x10^16[m]

Explanation:

To solve this problem we must use the formula of the average speed which relates distance to time, so we have

v = distance / time

where:

v = velocity = 3 x 10^8 [m/s]

distance = x [meters]

time = 6.45 [light years]

Now we have to convert from light-years to seconds in order to get the distance in meters.

$t = 6.45 [light-years]*365[\frac{days}{1light-year}]*24[\frac{hr}{1day}] *60[\frac{min}{1hr}]*60[\frac{seg}{1min} ] =203407200 [s]$

Now using the formula:

distance = v * time

distance = (3*10^8)*203407200

distance = 6.1022 x10^16[m]

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a satellite is traveling in a orbit around the earth. what change would cause it to experience more gravitational force from the

never [62]

The correct answer is:
<span>A. orbiting closer to the earths surface.

In fact, the gravitational force exerted by the Earth on the satellite is
</span> $F=G \frac{Mm}{r^2}$
<span>where
G is the gravitational constant
M is the Earth mass
m is the satellite mass
r is the distance of the satellite from the Earth's surface

We can see that, if the satellite orbits closer to the Earth's surface, its distance r from the centre of the planet decreases. But when r decreases, F (the gravitational force) increases, so A is the correct answer.</span>

7 0

2 years ago

A 912-kg car is being driven down a straight, level road at a constant speed of 31.5 m/s. When the driver sees a police cruiser

sergejj [24]

Answer:

786.6 N

Explanation:

mass of car, m = 912 kg

initial velocity of car, u = 31.5 m/s

final velocity of car, v = 24.6 m/ s

time, t = 8 s

Let a be the acceleration of the car

Use first equation of motion

v = u + a t

24.6 = 31.5 + a x 8

a = - 0.8625 m/s^2

Force, F = mass x acceleration

F = 912 x 0.8625

F = 786.6 N

Thus, the force on the car is 786.6 N.

8 0

2 years ago

A crate rests on a flatbed truck which is initially traveling at 17.9 m/s on a level road. The driver applies the brakes and the

Mamont248 [21]

Answer:

The minimum coefficient of friction required is 0.35.

Explanation:

The minimum coefficient of friction required to keep the crate from sliding can be found as follows:

$-F_{f} + F = 0$

$-F_{f} + ma = 0$

$\mu mg = ma$

$\mu = \frac{a}{g}$

Where:

μ: is the coefficient of friction

m: is the mass of the crate

g: is the gravity

a: is the acceleration of the truck

The acceleration of the truck can be found by using the following equation:

$v_{f}^{2} = v_{0}^{2} + 2ad$

$a = \frac{v_{f}^{2} - v_{0}^{2}}{2d}$

Where:

d: is the distance traveled = 46.1 m

$v_{f}$ : is the final speed of the truck = 0 (it stops)

$v_{0}$ : is the initial speed of the truck = 17.9 m/s

$a = \frac{-(17.9 m/s)^{2}}{2*46.1 m} = -3.48 m/s^{2}$

If we take the reference system on the crate, the force will be positive since the crate will feel the movement in the positive direction.

$\mu = \frac{a}{g}$

$\mu = \frac{3.48 m/s^{2}}{9.81 m/s^{2}}$

$\mu = 0.35$

Therefore, the minimum coefficient of friction required is 0.35.

I hope it helps you!

4 0

2 years ago

Which experiment best shows water’s ability to act as a solvent? raise the temperature of water and record its boiling point. fr

IrinaVladis [17]

The vanishing of an ionic solid (like table salt) would be an example of acting like a solvent

8 0

2 years ago

Read 2 more answers

FM radio ________________. a. had a somewhat shorter range than AM radio, but better sound quality. b. was widely adopted in the

svetlana [45]

Answer:

(A) FM Radio had a somewhat shorter ranger than AM radio, but better sound quality.

Explanation:

FM Radio was invented in 1933 by Edwin Armstrong who was an American engineer. FM stands for frequency modulation and AM stands for Amplitude Modulation.

FM is used for most broadcasts of music and FM radio stations use a very high-frequency range of radio frequencies.

In FM Radio, the sound is transmitted through changes in frequency. Both FM and AM radio signals experience frequent change in amplitude, they are far less noticeable on FM.

When switching between stations, FM antenna is alternating between different frequencies, and not amplitudes and this produces a much clearer sound and allows for smoother transitions with little to no audible static.

FM signals can be interfered by barriers and this could affect the signal strength. FM Radio signals are more clearer in a mountainous area that has no barrier.

AM radio was able to carry signals farther than AM radio.

6 0

3 years ago