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3 years ago

Calcium nitrate, Ca(NO3)2 , is a(n) ___________________.

Chemistry

2 answers:

Aleonysh [2.5K]3 years ago

6 0

B. Compound

Calcium nitrate is an inorganic compound

Serhud [2]3 years ago

5 0

It is a compound. This is because it is organic so it is therefore a compound.

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What would be the mass of a 45 cm^3 cube of Uranium?

Gnesinka [82]

Answer:

m = 859.5 g

Explanation:

d (Uranium) = 19.1 g/cm3

V = 45 cm3

m = V × d = 45 × 19.1 = 859.5 g

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3 years ago

Below are descriptions of different center voids of a solid fuel. Which design

Pavlova-9 [17]

C. A triangle will generate the most

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3 years ago

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Transuranium elements are artificial and may be prepared by a fusion process in which heavy nuclei are bombarded with light ones

Scilla [17]

Answer:

$_{97}^{345}\textrm{Bk}$

Explanation:

In a nuclear reaction, the total mass and total atomic number remains the same.

Am has an atomic number of 95. So correct reaction is:-

$^{343}_{95}\textrm{Am}+^{4}_{2}\textrm{He}\rightarrow ^A_Z\textrm{X}+2^1_0\textrm{n}$

To calculate A:

Total mass on reactant side = total mass on product side

343 + 4 = A + 2

A = 345

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

95 + 2 = Z + 0

Z = 97

Hence, the isotopic symbol of unknown element is $_{97}^{345}\textrm{Bk}$

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4 years ago

Consider the reaction.

vovangra [49]

Answer: The value of Keq for the reaction expressed in scientific notation is $1.6\times 10^{-5}$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.

For the given chemical reaction:

$2NOCl(g)\rightarrow 2NO(g)+Cl_2(g)$

The expression for $K_{eq}$ is written as:

$K_{eq}=\frac{[NO]^2\times [Cl_2]}{[NOCl]^2}$

$K_{eq}=\frac{(1.2\times 10^{-3})^2\times (2.2\times 10^{-3})}{(1.4\times 10^{-2})^2}$

$K_{eq}=1.6\times 10^{-5}$

The value of Keq for the reaction expressed in scientific notation is $1.6\times 10^{-5}$

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3 years ago

At 45.2 L cylinder containing C2H2F4 at a pressure of 3.00 atm is connected by the valve to 4060 mL cylinder containing N2H4 at

puteri [66]

The partial pressure of the N2H4 gas is 1.50 atm.

<h3>Dalton's law of partial pressure</h3>

From the Dalton's law of partial pressure, the total pressure of a mixture of gases is the sum of the individual partial pressures of all the gases present in the mixture.

We have the following;

C2H2F4 = 3.00 atm

N2H4 = c

Total pressure = 3.00 atm + 1.50 atm = 4.50 atm

Hence, the partial pressure of the N2H4 is N2H4.

Learn more about partial pressure: brainly.com/question/14623719

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2 years ago