1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KiRa [710]
2 years ago
9

6 A square silicon chip (k 150 W/m K) is of width w 5 mm on a side and of thickness t 1 mm. The chip is mounted in a substrate s

uch that its side and back surfaces are insulated, while the front surface is exposed to a coolant. If 4 W are being dissipated in circuits mounted to the back surface of the chip, what is the steady-state temperature difference between back and front surfaces
Engineering
1 answer:
bezimeni [28]2 years ago
5 0

Answer:

1.1⁰C

Explanation:

Width W = 5mm = 0.005

Thickness t = 1 mm = 0.001

K = thermal conductivity = 150W/m.K

P = q = heat transfer rate = 4W

We are to find the steady state temperature between the back and the front surface

We have to make these assumptions:

1. There is steady state conduction

2. The heat flow is of one dimension

3. The thermal conductivity is constant

4. The heat dissipation is uniform

We have:

∆t = t*P/k*W²

= (0.001m x 4W)/150x(0.005)²

= 0.004/0.00375

= 1.06667

This is approximately,

1.1⁰C

Thank you!

You might be interested in
Argon contained in a closed, rigid tank, initially at 33.7°C, 2.1 bar, and a volume of 4.2 m3, is heated to a final pressure of
Gelneren [198K]

Answer:

total heat required to raise pressure from 2.1 bar to 7.2 bar is 3295.336 kJ

Explanation:

given data

temperature t1 =  33.7°C = 306.7 K

pressure p1 = 2.1 bar

volume v1 = 4.2 m³

pressure p2 = 7.2 bar

ideal gas model k = 1.65

solution

we know heat transfer in constant volume is express as

Q = m × Cv × (t2-t1)   .............1

and here gas constant is 208.13 J/Kg.k

specific heat constant volume Cv = \frac{R}{K-1}  

put here value

Cv = \frac{208.13}{1.65-1}  

Cv = 320.2 J/Kg.k  

and

we get mass of argon gas m is

P1 × V1 = m × R × T1

m = \frac{2.1\times 10^5 \times 4.2}{208.13\times 306.7}  

m = 13.817 kg

and

t2 = \frac{7.2\times 306.7}{2.1}  

t2 = 1051.54  K

and

put equation 1 we get

Q = 13.81 × 320.2 × (1051.54-306.7)

Q = 3295.336 kJ

so total heat required to raise pressure from 2.1 bar to 7.2 bar is 3295.336 kJ

4 0
3 years ago
Sometimes, we need an amplifier with an accurate gain. Even using 1% tolerance resistors may not be sufficient to provide the re
vlabodo [156]

Answer:

The value of R_low is 13.1 kΩ while that of R_high is 36.8 kΩ

Explanation:

The diagram is as given as

The circuit is an inverting op amp for which the gain is given as

A_v=\dfrac{R_2+R}{R_1+R_z}

Here R2 is given as 450 kΩ.

R1 is given as 47 kΩ.

The gain is given as

A_v=-10\pm 0.5*\dfrac{10}{100}\\A_v=-10\pm 0.05

For the Lowest value of R the value of the internal resistance rz is 0 and the gain is -10+0.05 so

A_v=-\dfrac{R_2+R}{R_1+R_z}\\-10+0.05=-\dfrac{450+R_l_o_w}{47+0}\\-9.95=-\dfrac{450+R_l_o_w}{47+0}\\R_l_o_w=13.1

So the value of R_low is 13.1 kΩ

For the Highest value of R the value of the internal resistance rz is 1 kΩ and the gain is -10-0.05 so

A_v=-\dfrac{R_2+R}{R_1+R_z}\\-10-0.05=-\dfrac{450+R_{high}}{47+1}\\-10.05=-\dfrac{450+R_{high}}{47+1}\\R_{high}=36.8

So the value of R_high is 36.8 kΩ

5 0
3 years ago
To avoid rear wheel traction loss on a slippery surface ____________________.
Fofino [41]
By checking the low friction surfaces like sand or snow
3 0
3 years ago
How to build a backyard greenhouse popular mechanics?.
Anastaziya [24]

Answer:

Gardening enthusiasts can have these things and more by constructing a greenhouse in their backyards or acreages. You can choose a mini greenhouse, small greenhouse or even a barn greenhouse for whatever purposes you need it for.

Explanation:

Correct me if I'm wrong

6 0
2 years ago
Magnesium hydroxide is slightly soluble in water (Ksp = 1.8 x 10-11). NaOH is added to a solution of Mg(NO3)2 until a precipitat
Anastaziya [24]

Answer:

Explanation:

When NaOH is added to a solution of Mg(NO3)2 , a precipitate forms which will be Mg(OH)2 . When temperature of the solution is raised , Mg(OH)2 gets dissolved.

According to Le Chatelier principle , reaction tends to proceed towards the balance point when , the effect of external change in temperature or pressure etc is reduced.

Addition of heat , promotes dissolution. It is possible only when  the process of dissolution is endothermic. Additional dissolution on heating helps in reducing the temperature because , process of dissolution is endothermic.

Dissolution of Mg(OH)₂ is endothermic.

8 0
3 years ago
Other questions:
  • What is the minimum hose diameter of an ideal vacuum cleaner that could lift a 14 kg dog off the floor?
    15·2 answers
  • Which of the following tasks within an airline company are related to operations? A. crew scheduling. B. international monetary
    12·1 answer
  • Match the military operation to the category of satellite that would perform it.
    15·1 answer
  • The structure of PF3(C6H5)2 is trigonal bipyramidal, with one equatorial and two axial F atoms which interchange positions when
    15·1 answer
  • A tensile specimen with a 12mm initial diameter and 50mm gage length reaches maximum load at 90KN and fractures at 70KN
    14·1 answer
  • Which of the following allows team members to visualize a design model from a variety of perspectives?
    12·2 answers
  • Sea A una matriz 3x3 con la propiedad de que la transformada lineal x → Ax mapea R³ sobre R³.
    15·1 answer
  • Which tool is used to measure movement automotive
    8·1 answer
  • How to plot 0.45 gradation chart for sieve analysis ?
    12·1 answer
  • ________ delivers the precise number of parts to be assembled into a finished product at precisely the right time.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!