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gulaghasi [49]
3 years ago
5

Describe the 3 stages in the " life cycle" of a volcano

Chemistry
2 answers:
Greeley [361]3 years ago
6 0

Answer:

active,dormant,extinct

Explanation:

SpyIntel [72]3 years ago
3 0

active,dormant,extinct


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How long should i cook my pizza rolls?<br><br><br> pwease hewp im hunggy
mixer [17]

Answer:

depends on how many you have...

Explanation:

4 0
3 years ago
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Uranium has atomic number 92. Its most common isotope is 238U, but the form used in nuclear bombs and nuclear power plants is 23
Yakvenalex [24]

Explanation:

Atomic Number = Number of protons

Mass Number = Number of protons + Number of neutrons

Isotopes are simply atoms of an element with the same number of protons and different number of neutrons.

First Isotope -- 238U

Number of neutrons = Mass Number - Atomic Number

Number of neutrons =  238 - 92 = 146

Second Isotope -- 235U

Number of neutrons = Mass Number - Atomic Number

Number of neutrons =  235 - 92 = 143

3 0
3 years ago
As an employee of a summer sports camp, one of your jobs is to prepare the tank of vitamin water for use throughout the day. the
TiliK225 [7]
Given: 
Mixture of vitamin water = 75% pure water & 25% concentrated vitamin drink.  
To find:  
Quantity of water to be added to 16 gallons of concentrated vitamin drink to prepare a tank of vitamin water.  
Solution: 
Let total amount of mixture be x. 
25% of x = 16 gallons (from given information)  
When 25% of x is 16 gallons, the remaining 75% of x will be calculated as below:
 (16/25)*75 = 48 
 Answer: 75% of x = 48 gallons. This means 48 gallons pure water is required to be added to mixture to prepare a tank of vitamin water.
3 0
3 years ago
Write the balanced chemical equation between H2SO4 and KOH in aqueous solution. This is called a neutralization reaction and wil
emmainna [20.7K]

Answer:

0.166M

Explanation:

In a neutralization, the acid, H₂SO₄, reacts with a base, KOH, to produce a salt, K₂SO₄ and water. The reaction is:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

To solve this problem, we need to determine moles of H2SO4 and moles of KOH that reacts to find the moles of sulfuric acid that remains after the reaction:

<em>Moles H2SO4:</em>

0.650L * (0.430mol /L) = 0.2795moles H2SO4

<em>Moles KOH:</em>

0.600L * (0.240mol / L) = 0.144 moles KOH

Moles of sulfuric acid that reacts with 0.144 moles of KOH are:

0.144 moles KOH * (1mol H2SO4 / 2 mol KOH) = 0.072 moles of H2SO4 react.

And remain:

0.2795moles H2SO4 - 0.072moles H2SO4 = 0.2075 moles of H2SO4 reamains.

In 0.650L + 0.600L = 1.25L:

Molar concentration of sulfuric acid:

0.2075 moles of H2SO4 / 1.25L =

<h3>0.166M</h3>
7 0
2 years ago
How to answer this ?
nadezda [96]
You multiply (4×10)by*
6 0
3 years ago
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