Answer:
1. Yes
2.The solubility of X is 34.55g/L
Explanation:
Solubility of solute refers to how readily a solute will dissolve in a solvent at a particular temperature. Its the amount of moles or grams required to saturate 1dm or 1 Litre of water.
From the problem, when the liquid was drained off and amount of X which didn't dissolve was measured, it weighed 0.008kg, this means out of 0.027kg, 0.027-0.008 actually dissolved
= 0.019kg*1000 = 19g.
if 19g is required to saturate 550mL at 30°C,
then will saturate 1L
= 34.545g will saturate 1Litre
The solubility thus is 34.55g/L
Answer: A
1.68 N
Explanation:
F = ma = 0.024(70.0) = 1.68 N
Answer:
The answer is "0.0000190 and 2.7 J".
Explanation:
Given:
by putting the value into the above formula so, the value is 2.7 J
Answer: C.)
Explanation:
i got it right on a unit test!
but it might be something else if there arranged different!
sorry!