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jeka57 [31]
3 years ago
14

A milliammeter has an internal resistance of 5ohms and

Physics
1 answer:
Vikentia [17]3 years ago
7 0

Answer:

Rs = 0.02008 Ω = 20.08 mΩ

Explanation:

The range of an ammeter can be increased by connecting a small shunt resistance to it in a series combination. This shunt resistance can be calculated by the following formula:

Rs = \frac{I_gR_g}{I - I_g}

where,

R_s = value of shunt resistance = ?

I_g = current range of ammeter = 20 mA = 0.02 A

I = Required range of ammeter = 5 A

R_g = Resistance of ammeter = 5 ohms

Therefore,

R_s = \frac{(0.02\ A)(5\ ohms)}{5\ A-0.02\ A}

<u>Rs = 0.02008 Ω = 20.08 mΩ</u>

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