Alcohol consumption tends to cause what kind of behavior

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Bad White [126]

The answer would be d

7 0

3 years ago

Read 2 more answers

Graph the line that passes through the points (-4, -1) and (-4, 2) and determine the equation of the line.

My name is Ann [436]

Answer:

X = -4

Step-by-step explanation:

7 0

3 years ago

(2x-7)-(4x^2+6x-3)+(x^2+4)

masha68 [24]

Answer:

$-3x^2-4x$

Step-by-step explanation:

Simplify:

$\left(2x-7\right)-\left(4x^2+6x-3\right)+\left(x^2+4\right)$

$=2x-7-\left(4x^2+6x-3\right)+x^2+4$

Group same factor:

$=-\left(4x^2+6x-3\right)+x^2+2x-7+4$

Add :

$=-\left(4x^2+6x-3\right)+x^2+2x-3$

Apply the distributive law: -(a+b) = -a - b

$-\left(4x^2+6x-3\right)=-4x^2-6x+3$

$=-4x^2-6x+3+x^2+2x-3$

Group same factor:

$=-4x^2+x^2-6x+2x+3-3$

Subtract:

$=-4x^2+x^2-6x+2x$

Add:

$=-3x^2-6x+2x$

Group same factor:

$=-3x^2-4x$

Hence answer = $-3x^2-4x$

<u><em>~lenvy~</em></u>

8 0

2 years ago

FEE

frozen [14]

Answer:

The equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

$y+2=\frac{3}{4}\left(x+4\right)$

$3x - 4y = -4$

Step-by-step explanation:

The slope-intercept form of the line equation

$y = mx+b$

where

m is the slope

b is the y-intercept

Given the line

3x - 4y = 7

writing in the slope-intercept form

4y = 3x - 7

dividing both sides by 4

4y/4 = 3/4x - 7/4

y = 3/4x - 7/4

Now, comparing with the slope-intercept form of the line equation

y = 3/4x - 7/4

The slope of the line m = 3/4

We know that parallel lines have the same slopes.

Therefore, the slope of the parallel line is: 3/4

now we have,

The point (-4, -2)

The slope m of parallel line = 3/4

Given the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where m is the slope of the line and (x₁, y₁) is the point

substituting (-4, -2) and m = 3/4 in the point-slope form of line equation

$\:y-\left(-2\right)=\frac{3}{4}\left(x-\left(-4\right)\right)$

$y+2=\frac{3}{4}\left(x+4\right)$

Thus, the equation in the point-slope form of the line equation is:

$y+2=\frac{3}{4}\left(x+4\right)$

Simplifying the equation

$y+2=\frac{3}{4}\left(x+4\right)$

Subtract 3 from both sides

$y+2-2=\frac{3}{4}\left(x+4\right)-2$

$y=\frac{3}{4}x+1$

Multiplying the equation by 4

$4y = 3x + 4$

$3x - 4y = -4$

Therefore, the equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

$y+2=\frac{3}{4}\left(x+4\right)$

$3x - 4y = -4$

7 0

3 years ago

Given tan θ = 2 and sin θ < 0. Find cos(θ +pi/4)

Lera25 [3.4K]

Answer:

√10 / 10

Step-by-step explanation:

tan θ > 0 and sin θ < 0, so θ is in quadrant III. That means cos θ < 0.

cos(θ + π/4)

Use angle sum formula.

cos θ cos(π/4) − sin θ sin(π/4)

½√2 cos θ − ½√2 sin θ

Factor.

½√2 cos θ (1 − tan θ)

½√2 cos θ (1 − 2)

-½√2 cos θ

Write in terms of secant.

-½√2 / sec θ

Use Pythagorean identity (remember that cos θ < 0).

-½√2 / -√(1 + tan²θ)

-½√2 / -√(1 + 2²)

½√2 / √5

√10 / 10

5 0

3 years ago