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sergey [27]
3 years ago
12

A ___ is the part of the solution that usually stats as a solid and dissolves in solvent ?

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
4 0

a substance is the part of the solutin


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According to the Energy Information Administration (EIA), oil accounts for what percentage of the U.S. energy mix?
stich3 [128]

Answer: answer is b 29%

Explanation:

7 0
3 years ago
An element (gas) used to make colorfully lit advertising signs
AleksAgata [21]
The correct answer is neon
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3 years ago
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if one mole of calcium carbonate (the limiting reactant) is used, how much calcium chloride should the reaction produce? look at
salantis [7]

Answer:

The answer to your question is <u>111 g of CaCl₂</u>

Explanation:

Reaction

                 2HCl  +  CaCO₃   ⇒    CaCl₂  +  CO₂  +  H₂O

Process

1.- Calculate the molecular mass of Calcium carbonate and calcium chloride

CaCO₃ = (1 x 40) + (1 x 12) + ((16 x 3) = 100 g

CaCl₂ = (1 x 40) + (35.5 x 2) = 111 g

2.- Calculate the amount of calcium chloride produced using proportions.

The proportion CaCO₃ to CaCl₂ is   1 : 1.

                      100 g of CaCO₃  ------------- 111 g of CaCl₂

Then 111g of CaCl₂ will be produced.

5 0
3 years ago
Hydrogen reacts with an element to form a compound. Which element would have the most valence electrons and also be able to reac
pantera1 [17]

Answer:

Chlorine

Explanation:

Hello.

In this case, for the given elements, we are able to know that oxygen has 6 valence electrons, chlorine 7, nitrogen 5 and neon 8, therefore neon is not able to react as it already has 8 valence electrons. Besides, the element having the most valence electrons is chlorine and its reaction with hydrogen forms hydrogen chloride as shown below:

H_2(g)+Cl_2(g)\rightarrow 2HCl(g)

Therefore, the required element is chlorine.

Regards.

5 0
3 years ago
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Ammonia is a weak base. if the initial concentration of ammonia is 0.150 m and the equilibrium concentration of hydroxide is 0.0
NARA [144]
Answer is: Kb for ammonia is 1.73·10⁻⁵.<span>
Chemical reaction of ammonia in water: NH</span>₃ + H₂O → NH₄⁺ + OH⁻<span>.
Kb(NH</span>₃) = ?<span>.
c</span>₀(NH₃<span>) = 0.150 M.
c(NH</span>₄⁺) = c(OH⁻<span>) = 0.0016 M.
c(NH</span>₃<span>) = 0.150 M - 0.0016.
</span>c(NH₃) = 0.1484 M.<span>
Kb</span>(NH₃) = c(NH₄⁺) · c(OH⁻) / c(NH₃<span>).
Kb</span>(NH₃) = (0.0016 M)² / 0.1484 M.
Kb(NH₃) = 1.73·10⁻⁵.<span>

</span>
7 0
3 years ago
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