Answer:
A. The reaction will proceed forward forming more CH4
B. The reaction will proceed forward forming more CH4
C. Since the reaction is exothermic, raising the temperature will cause the reaction to proceed backward, thus forming C and H2.
D. Lowering the volume makes the gas particles to be more close together thereby enhancing their collisions leading to reaction. Therefore the reaction will proceed forward forming more CH4
E. Catalyst only reduce the activation energy so the reaction can proceed faster. The reaction will proceed forward forming.
F. The following will favour CH4 at equilibrium
i. Catalyst to the reaction mixture,
ii. Both adding more H2 to the reaction mixture and lowering the volume of the reaction mixture
iii. Adding more C to the reaction mixture.
Answer:
686.43363984 is the answer when 7.8 moles is converted.
Answer:
The answer to your question is: V2 = 1.94 l
Explanation:
Data
V1 = 2.42 l
T1 = 25°C
P1 = 1 atm
V2 = ?
T2 = 25 -11 = 14°C
P2 = 1(0.7) = 0.7 atm
Formula
P1V1/T1 = P2V2/T2
Clear V2 from the equation
V2 = P1V1T2/ P2T1
V2 = (1)((2.42)(14) / (0.7)(25)
V2 = 33.88 / 17.5
V2 = 1.94 l
The correct answer to this question is this one:
HF (hydrofluoric acid) is a weak acid.
SO4 2- (sulfite ion) is a weak base
F- (fluoride anion) is a very weak base
HSO4 - (hydrogen sulfate) is a weak acid
Conjugate acid of HF = H2F+ (dihydrogen fluoride)
Conjugate base of HF = F- (fluoride)
Conjugate acid of SO4 2- = HSO4- (hydrogen sulfite)
SO4 2- does not have a conjugate base because you can't take away any H+
Conjugate acid of F- = HF (hydrofluoric acid)
F- does not have a conjugate base because you can't take away any H+
Conjugate acid of HSO4- = H2SO4 (sulphuric acid)
Conjugate base of HSO4- = SO4 2- (sulfite)
In very simple words:
Conjugate acid --> you add an H+
Conjugate base --> you take away an H+