Question

Two narrow slits are illuminated by a laser with a wavelength of 593 nm. The interference pattern on a screen located x = 4.80 m away shows that the fourth-order bright fringe is located y = 8.20 cm away from the central bright fringe. Calculate the distance between the two slits.

Answer 1

Answer:

The distance is  $d = 1.39 *10^{-4} \ m$

Explanation:

From the question we are told that

   The wavelength is  $\lambda = 593 \ nm = 593 *10^{-9} \ m$

    The distance of the screen is   x  =  4.80 m

    The  location of the fourth order bright fringe is  y  =  8.20 cm = 0.082 m

    The order of the fringe is  n  =  4

   

Generally the position of a fringe with respect to the central fringe is mathematically represented as

           $y = \frac{ n * x * \lambda }{d}$

Where d is the distance between the slits, so making d the subject

          $d = \frac{\lambda * x * n }{ y }$

substituting values

          $d = \frac{ 593 *10^{-9} * 4.80 * 4 }{ 0.082 }$

           $d = 1.39 *10^{-4} \ m$