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ser-zykov [4K]
3 years ago
13

How do the nuclei of covalently bonded atoms help keep the bond together?

Physics
2 answers:
Mkey [24]3 years ago
5 0

Answer:

the answer is d

Explanation:

and BOOM! the right answer!

kifflom [539]3 years ago
3 0

Answer;

D. Positive particles in the nucleus are attracted to shared electrons, so the atoms stay close together

Explanation;

-Covalent bonds hold atoms together because the attraction between the positively charged nuclei and the negatively charged shared electrons is greater than the repulsions between the nuclei themselves.

-The attraction between the positively charged nuclei and the negatively charged shared electrons is greater than the repulsions between the nuclei themselves.

-As two atoms approach each other, the electrons in their outer shells start to notice the nucleus of the other atom. As a result, they become attracted not only to their own nucleus, but to the nucleus of the other atom as well. The electrons then tend to spend more of their time in between the two nuclei, instead of just around their own nucleus.

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When an ideal gas does positive work in its surroundings, which of the ga's quantities increases?
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I think it's B hope it helps
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Vikki [24]

Answer:

The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.

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5 0
3 years ago
Read 2 more answers
An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It is accelerated from rest through a potential difference that
zzz [600]

Answer with Explanation:

We are given that

Charge on alpha particle=q=2 e=2\times 1.6\times 10^{-19} C

1 e=1.6\times 10^{-19} C

Mass of alpha particle=m=6.64\times 10^{-27} kg

Potential difference,V=1.97\times 10^6 V

Magnetic field,B=3.49 T

a.Speed of alpha particle=v=\sqrt{\frac{2 qV}{m}}

By using the formula

v=\sqrt{\frac{2\times 2\times 1.6\times 10^{-19}\times 1.97\times 10^6}{6.64\times 10^{-27}}

v=1.38\times 10^7 m/s

b.Magnetic force,F=qvB=2\times 1.6\times 10^{-19}\times 1.38\times 10^7\times 3.49=1.5\times 10^{-11} N

F=1.5\times 10^{-11} N

c.Radius of circular path, r=\frac{mv^2}{F}

r= \frac{6.64\times 10^{-27}\times (1.38\times 10^7)^2}{1.5\times 10^{-11}}

r=0.084 m

5 0
3 years ago
Complete the following sentences.
MrMuchimi
  1. force pull the ball towards it with a force called gravity. <em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
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