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ser-zykov [4K]
3 years ago
13

How do the nuclei of covalently bonded atoms help keep the bond together?

Physics
2 answers:
Mkey [24]3 years ago
5 0

Answer:

the answer is d

Explanation:

and BOOM! the right answer!

kifflom [539]3 years ago
3 0

Answer;

D. Positive particles in the nucleus are attracted to shared electrons, so the atoms stay close together

Explanation;

-Covalent bonds hold atoms together because the attraction between the positively charged nuclei and the negatively charged shared electrons is greater than the repulsions between the nuclei themselves.

-The attraction between the positively charged nuclei and the negatively charged shared electrons is greater than the repulsions between the nuclei themselves.

-As two atoms approach each other, the electrons in their outer shells start to notice the nucleus of the other atom. As a result, they become attracted not only to their own nucleus, but to the nucleus of the other atom as well. The electrons then tend to spend more of their time in between the two nuclei, instead of just around their own nucleus.

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The weakest gravitational force caused by the Moon is called the __________, which is found at the point on Earth farthest from
skad [1K]
This is called Nadir.
4 0
2 years ago
A circular loop of wire 78 mm in radius carries a current of 114 A. Find the (a) magnetic field strength and (b) energy density
Finger [1]

Explanation:

It is given that,

Radius of loop, r = 78 mm = 0.078 m

Current, I = 114 A

(a) Magnetic field strength of the circular loop is given by :

B=\dfrac{\mu_oI}{2R}

B=\dfrac{4\pi \times 10^{-7}\times 114}{2\times 0.078}

B = 0.000918 T

or

B=9.18\times 10^{-4}\ T

(b) Energy density at the center of the loop is given by :

U=\dfrac{B^2}{2\mu_o}

U=\dfrac{(0.000918)^2}{2\times 4\pi \times 10^{-7}}

U=0.335\ J/m^3

Hence, this is the required solution.

7 0
3 years ago
Alice's friends Bob and Charlie are having a race to a distant star 10 light years away. Alice is the race official who stays on
hodyreva [135]

Solution :

The distance between the starting point and the end point, L_0 = 10 light years

But due to the relativistic motion of Bob and Charlie, the distance will be reduced following the Lorentz contraction. The contracted length will be different since they are moving with different speeds.

For Bob,

Speed of Bob's rocket with respect to Alice, L_b = 0.7  \ c

So the distance appeared to Bob due to the length contraction,

$L_b=L_0\sqrt{1-\frac{V_b^2}{c^2}$

$L_b=10\times \sqrt{1-0.49} \ Ly$

    $=7.1 \ Ly$

Therefore, the time required to finish the race by Bob is

$t_b = \frac{L_b}{V_b}$

  $=\frac{7.1 \ c}{0.7 \ c}$

  = 10.143 year

For Charlie,

Speed of Charlie's rocket with respect to Alice, L_c = 0.866 \ c

So the distance appeared to Charlie due to the length contraction,

$L_b=L_0\sqrt{1-\frac{V_c^2}{c^2}$

$L_b=10\times \sqrt{1-0.75} \ Ly$

    $=5 \ Ly$

The time required to finish the race by Charlie is

$t_b = \frac{L_c}{V_c}$

  $=\frac{5 \ c}{0.866 \ c}$

  = 5.77 year

5 0
3 years ago
Look at the attached photo:
pshichka [43]

Answer:

C) Mass of the ball

Explanation:

Independent variable is the variable the researcher changes.

Since Martin is testing the mass of the ball, he'll be using different balls and that is the only thing he changes.

The distance traveled by the ball is the dependent variable since it depends on the mass of the ball.

The height and length of the ramp are the constant variables since that's the only ones that remain the same throughout this experiment.

7 0
3 years ago
Who ever gets this right will get a brainlest, science
taurus [48]

Answer:

b

Explanation:

5 0
3 years ago
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