According to the law of conservation of energy, what will most likely happen in a closed system?

What are the conditions under which the resultant of three coplanar forces is zero?<br>

serg [7]

When three or more coplanar forces are acting at a point and the vector diagram closes, there is no resultant. The forces acting at the point are in equilibrium.

4 0

2 years ago

The speed of a box traveling on a horizontal friction surface changes from vi = 13 m/s to vf = 11.5 m/s in a distance of d = 8.5

KiRa [710]

Answer:

0.68 s

Explanation:

We are given that

Initial velocity of box= $u=13m/s$

Final velocity of box=v=11.5 m/s

Distance=d=8.5 m

We have to find the time taken by box to slow by this amount.

We know that

$v^2-u^2=2as$

Substitute the values

$(11.5)^2-(13)^2=2a(8.5)$

$132.25-169=17a$

$-36.75=17a$

$a=\frac{-36.75}{17}=-2.2m/s^2$

We know that

Acceleration= $a=\frac{v-u}{t}$

Substitute the values

$-2.2=\frac{11.5-13}{t}$

$-2.2=\frac{-1.5}{t}$

$t=\frac{1.5}{2.2}=0.68 s$

Hence, the time taken by box to slow by this amount=0.68 s

8 0

3 years ago

A car, traveling at , encounters a dip in the road. The radius of curvature at the bottom of the dip is . Each of the car’s four

labwork [276]

Answer:

spring deflection is x = (v2 / R + g) m / 4

Explanation:

We will solve this problem with Newton's second law. Let's analyze the situation the car goes down a road and finds a dip (hollow) that we will assume that it has a circular shape in the lower part has the car weight, elastic force and a centripetal acceleration

Let's write the equations on the Y axis of this description

Fe - W = m $a_{c}$

Where Fe is elastic force, W the weight and $a_{c}$ the centripetal acceleration. The elastic force equation is

Fe = - k x

4 (k x) - mg = m v² / R

The four is because there are four springs, R is theradio of dip

We can calculate the deflection (x) of the springs

x = (m v2 / R + mg) / 4

x = (v2 / R + g) m / 4

5 0

3 years ago

In the diagram, the arrow shows the movement of electric charges through a wire connected to a battery.

solong [7]

Due to difference in electric potential.

<h3>What is Potential difference?</h3>

The amount of work in an electrical field to move a unit charge from one place to another is known as the electrical potential difference.

Here , the potential difference is the difference in electric potential between two charged substances.

Current is the flow of charges from one end end to another end of a conducting wire connected across a two terminals of a battery.

The potential difference is [provided by the battery across the two terminals due which the charges flow.

Current flow is from positive to negative terminals, indicating the movement of positive charges in that direction.

Hence , potential difference causes the electric charges to flow from one end of the battery .

Learn more about the flow of current : brainly.com/question/2264542

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6 0

1 year ago

Initially, a particle is moving at 5.25 m/s at an angle of 35.5Â° above the horizontal. Three seconds later, its velocity is 6.0

ivolga24 [154]

Answer:

a =( -0.32 i ^ - 2,697 j ^) m/s²

Explanation:

This problem is an exercise of movement in two dimensions, the best way to solve it is to decompose the terms and work each axis independently.

Break down the speeds in two moments

initial

v₀ₓ = v₀ cos θ

v₀ₓ = 5.25 cos 35.5

v₀ₓ = 4.27 m / s

$v_{oy}$ = v₀ sin θ

$v_{oy}$ = 5.25 sin35.5

$v_{oy}$ = 3.05 m / s

Final

vₓ = 6.03 cos (-56.7)

vₓ = 3.31 m / s

$v_{y}$ = v₀ sin θ

$v_{y}$ = 6.03 sin (-56.7)

$v_{y}$ = -5.04 m / s

Having the speeds and the time, we can use the definition of average acceleration that is the change of speed in the time order

a = ( $v_{f}$ - v₀) /t

aₓ = (3.31 -4.27)/3

aₓ = -0.32 m/s²

$a_{y}$ = (-5.04-3.05)/3

$a_{y}$ = -2.697 m/s²

6 0

3 years ago