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tatiyna
2 years ago
8

Many college students have a mini-fridge in their dorm room. A standard mini fridge costs roughly $100, uses about 100 watts of

electricity per hour when it is running, and can be expected to last for 5 years. The refrigerator is plugged into an electrical socket 24 hours a day, but is usually running only about 12 hours per day. Assume that electricity costs $0.10/kWh.
(a) Calculate the lifetime monetary cost of owning and operating the refrigerator.
(b) Assume that the electricity used to power the refrigerator comes from a coal-burning power plant. One metric ton of coal contains 29.3 GJ (8,140 kWh) of energy. Because of the inefficiency of electricity generation and transmission, only one-third of the energy in coal reaches the refrigerator. How many tons of coal are used to power the refrigerator during its lifetime?
(c) Assume that 15 percent of the mass of the coal burned in the power plant ends up as coal ash, a potentially toxic mixture that contains mercury and arsenic. How many tons of coal ash are produced as a result of the refrigerator's electricity use over its lifetime?
(d) What externalities does your answer from part (a) not include? Describe one social and one environmental cost associated with using this appliance.
(e) Describe two ways a college student could reduce the electricity use associated with having a mini fridge in his or her dorm room.
Physics
1 answer:
borishaifa [10]2 years ago
4 0

The amount of coal burnt to operate the mini fridge is 0.81 metric tons.

<h3>What is energy cost?</h3>

The term energy cost refers to the monetary cost of operating a particular electrical appliance. Let us now answer the questions one after the other.

a) Power consumption per hour = 100 watt or 0.1kW. To operate it for an hour we have  0.1kWhr × $0.10/kWh = 0.01$ Since it operates for twelve hours a day 12(0.01$)= 0.12$ per day. In five years; 0.12$× 5 × 365 = 219 $.

b) Electricity used for the five years = 5 × 365 × 12 × 0.1kWhr = 2190 kWhr

Since 1 metric ton of coal produces 2713 kWh(considering energy losses)

x metric tons of coal produces 2190 kWhr

x = 1 metric ton × 2190 kWhr/2713 kWh

x = 0.81 metric tons

c) In part 1 we did not include the cost of the environmental damage caused by the mining of coal and the social inconveniences caused by the sound of the mini fridge.

d) The college student could reduce the electricity use associated with having a mini fridge in his or her dorm room by turning it off for some hours within the day.

Learn more about cost of electricity: brainly.com/question/13498414

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The diagram below shows different weights on the see-saw. Will the see-saw move?
oee [108]

Answer:

yes it will

Explanation:

8 0
2 years ago
A baseball is batted from a height of 1.09 m with a speed of
kobusy [5.1K]

(a) The horizontal and vertical components of the ball’s initial velocity is 37.8 m/s and 12.14 m/s respectively.

(b) The maximum height above the ground reached by the ball is 8.6 m.

(c) The distance off course the ball would be carried is 0.38 m.

(d) The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.

<h3>Horizontal and vertical components of the ball's velocity</h3>

Vx = Vcosθ

Vx = 39.7 x cos(17.8)

Vx = 37.8 m/s

Vy = Vsin(θ)

Vy = 39.7 x sin(17.8)

Vy = 12.14 m/s

<h3>Maximum height reached by the ball</h3>

H = \frac{v^2 sin^2(\theta)}{2g} \\\\H = \frac{(39.7)^2 \times (sin17.8)^2}{2(9.8)} \\\\H = 7.51 \ m

Maximum height above ground = 7.51 + 1.09 = 8.6 m

<h3>Distance off course after 2 second </h3>

Upward speed of the ball after 2 seconds, V = V₀y - gt

Vy = 12.14 - (2x 9.8)

Vy = - 7.46 m/s

Horizontal velocity will be constant = 37.8 m/s

Resultant speed of the ball after 2 seconds = √(Vy² + Vx²)

V = \sqrt{(-7.46)^2 + (37.8)^2} \\\\V = 38.53 \ m/s

<h3>Resultant speed of the ball and crosswind</h3>

V = \sqrt{38.52^2 + 4^2} \\\\V = 38.72 \ m/s

<h3>Distance off course the ball would be carried</h3>

d = Δvt = (38.72 - 38.53) x 2

d = 0.38 m

The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.

Learn more about projectiles here: brainly.com/question/11049671

5 0
1 year ago
Strontium 3890Sr has a half-life of 28.5 yr. It is chemically similar to calcium, enters the body through the food chain, and co
patriot [66]

Answer:

Thus the time taken is calculated as 387.69 years

Solution:

As per the question:

Half life of ^{3890}Sr\, t_{\frac{1}{2}} = 28.5 yrs

Now,

To calculate the time, t in which the 99.99% of the release in the reactor:

By using the formula:

\frac{N}{N_{o}} = (\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where

N = No. of nuclei left after time t

N_{o} = No. of nuclei initially started with

\frac{N}{N_{o}} = 1\times 10^{- 4}

(Since, 100% - 99.99% = 0.01%)

Thus

1\times 10^{- 4} = (\frac{1}{2})^{\frac{t}{28.5}}}

Taking log on both the sides:

- 4 = \frac{t}{28.5}log\frac{1}{2}

t = \frac{-4\times 28.5}{log\frac{1}{2}}

t = 387.69 yrs

5 0
3 years ago
Suatu gas memiliki volume 2 m³ dipanaskan dengan kondisi isobarik sehingga volumenya menjadi 5,5 m³ jika tekanan 4 atmosfer hitu
Ivan

Answer:

Sorry if wrong.............

5 0
3 years ago
a gym consists of a rectangular region with a semi-circle on each end. if the perimeter of the room is to be a 200 m running tra
Nikolay [14]

The dimensions of the rectangle are:

l = 50 m

b = 100/\pi m

<h3>What is a perimeter in math?</h3>

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

<h3>How do we find a perimeter of a rectangle?</h3>

The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.

<h3>Given:</h3>

As per the question:

Perimeter of the room is given as P = 200 m

The region is rectangular having a semicircle at each end.

Now,

Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.

Then, Area of the given rectangle, A = lb

Perimeter of the room, P is =\pi r+l+\pi r+l=2\pi r+2l=\pi b+2l

Therefore,  \pi b+2l=200

b=(200-2l)/\pi

Now,

Area, A = l(200-2l)/\pi=(200l-2l^{2} )/\pi

Now, differentiate A w.r.t l:

Again differentiating w.r.t 'l', we get:

d^{2} A/dl^{2} =-4l/\pi< 0

Thus we get maximum are when dA/dl=0

Therefore,

(200-4l)/\pi=0

l = 50 m

Now, from

\pi b+2l=200

\pi b=200-2*50

b=100/\pi

r=b/2=50/\pi

To know more about area of a recatangle, visit the link

brainly.com/question/20693059

#SPJ4

4 0
1 year ago
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