Answer:

Explanation:
As we know that here final equilibrium temperature is 0 degree C
so we can use energy conservation here
heat given by the cube = heat absorbed by the ice
so we have

so here we have



Answer:
The magnitude of force must you apply to hold the platform in this position = 888.89 N
Explanation:
Given that :
Workdone (W) = 80.0 J
length x = 0.180 m
The equation for this work done by the spring is expressed as:

Making the spring constant
the subject of the formula; we have:

Substituting our given values, we have:


The magnitude of the force that must be apply to the hold platform in this position is given by the formula :


F = 888.89 N
We have:
Initial velocity (u) = 1.6 m/s
Constant acceleration (a) = 0.33 m/s²
Time (t) = 3.6 sec
There are five constant acceleration equations that would help us to find the velocity:





Since we have

and we want

We will use the first formula



m/s