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Scorpion4ik [409]
3 years ago
7

A force F of magnitude 2x^3 is applied to stop a particle moving with an initial velocity of v0. The particle travels from x=0 t

o x= D in coming to a stop after the force F is applied. The work done by F is:a) 1/2 D^3b) -D^4c) D^4d) 2D^3e) -D^3f) -1/2 D^4g) 1/2D^4h) -1/2D^3
Physics
1 answer:
3241004551 [841]3 years ago
5 0

Answer:

Explanation:

Given that

F=2x³

Work is given as

The range of x is from x=0 to x=D

W=-∫f(x)dx

Then,

W=-∫2x³dx from x=0 to x=D

W=- 2x⁴/4 from x=0 to x=D

W=-2(D⁴/4-0/4)

W=-D⁴/2

W=1/2D⁴

The correct answer is F

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Choose the correct definitions of speed, velocity, and acceleration. Check all that apply. Acceleration tells us in which direct
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We have thatThe options that define Speed, Velocity,Acceleration.

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Options

B,D,E

From the question we are told

Choose the correct definitions of speed, velocity, and acceleration. Check all that apply.

  • Acceleration tells us in which direction the object is going. Speed is the rate of change of velocity in time.
  • Acceleration is the rate of change of velocity in time.
  • Velocity is used to describe changes in the movement direction of the object. Acceleration tells us how far the object will go in a certain amount of time.
  • Velocity is used to describe how fast the object is moving and tells us in which direction it is going.
  • Speed is used to describe how fast the object is moving.
  • Velocity is the rate of change of speed in time.

Speed is used to describe how fast the object is moving and tells us in which direction it is going.

Generally

  • Acceleration is the rate of change of velocity in time.
  • Velocity is used to describe how fast the object is moving and tells us in which direction it is going.
  • Speed is used to describe how fast the object is moving without its direction in consideration

Hence

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2 years ago
Find the intensity of the electromagnetic wave described in each case. (a) an electromagnetic wave with a wavelength of 630 nm a
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Find the intensity of the electromagnetic wave described in each case.

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(b) an electromagnetic wave with an angular frequency of 6.3 ✕ 1018 rad/s and a peak magnetic field magnitude of 10−10 T.

3 0
3 years ago
A sound wave has frequency 620 Hz and wavelength 10.5 m. What is the speed of sound waves?
olasank [31]

Answer:

14

Explanation:

A sound wave in a steel rail has a frequency of 620 Hz and a wavelength of 10.5 m. What is the speed of sound in steel? U f = ? S f = 3 x 108 m/s) / 0.06 m 14 so it will be 14

7 0
3 years ago
In a 100 mm diameter horizontal pipe, a venturimeter of 0.5 contraction ratio has been fitted. The head of water on the meter wh
horrorfan [7]

Answer:

the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

Explanation:

Given:

Diameter of the pipe = 100mm = 0.1m

Contraction ratio = 0.5

thus, diameter at the throat of venturimeter = 0.5×0.1m = 0.05m

The formula for discharge through a venturimeter is given as:

Q=C_d\frac{A_1A_2}{\sqrt{A_1^2-A_2^2}}\sqrt{2gh}

Where,

C_d is the coefficient of discharge = 0.97 (given)

A₁ = Area of the pipe

A₁ = \frac{\pi}{4}0.1^2 = 7.85\times 10^{-3}m^2

A₂ = Area at the throat

A₂ = \frac{\pi}{4}0.05^2 = 1.96\times 10^{-3}m^2

g = acceleration due to gravity = 9.8m/s²

Now,

The gauge pressure at throat = Absolute pressure - The atmospheric pressure

⇒The gauge pressure at throat = 2 - 10.3 = -8.3 m (Atmosphric pressure = 10.3 m of water)

Thus, the pressure difference at the throat and the pipe = 3- (-8.3) = 11.3m

Substituting the values in the discharge formula we get

Q=0.97\frac{7.85\times 10^{-3}\times 1.96\times 10^{-3}}{\sqrt{7.85\times 10^{-3}^2-1.96\times 10^{-3}^2}}\sqrt{2\times 9.8\times 11.3}

or

Q=\frac{0.97\times15.42\times 10^{-6}\times 14.88}{7.605\times 10^{-3}}

or

Q = 29.28 ×10⁻³ m³/s

Hence, the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

5 0
3 years ago
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