Answer:
(A) 11 m/s
(B) 1.3 m
Explanation:
Horizontal range, R = 9.6 m
Angle of projection, theta = 28 degree
(A)
Use the formula of horizontal range
R = u^2 Sin 2 theta / g
u^2 = R g / Sin 2 theta
u^2 = 9.6 × 9.8 / Sin ( 2 × 28)
u = 10.65 m/s
u = 11 m/s
(B)
Use the formula for maximum height
H = u^2 Sin ^2 theta / 2g
H =
10.65 × 10.65 × Sin^2 (28) / ( 2 × 9.8)
H = 1.275 m
H = 1 .3 m
<u>Answer:</u>
<em>Jody will have strong bones and show muscle hypertrophy.
</em>
<u>Explanation:</u>
Long distance running practiced regularly helps in <em>increasing the strength of bones</em>. Muscular hypertrophy is the increase in mass of skeletal muscles due to the increase in the size of myofibrils or increase in muscle glycogen storage. <em>Strength training exercises</em> performed regularly induce muscular hypertrophy.
During strength <em>training exercises muscles</em> undergo contraction and repeated contraction breaks muscle fibres. New muscle fibres are added as a means of repair and this happens at the relaxing phase of muscles. More muscle fibres are added to <em>compensate the damage and thus muscle mass increases.
</em>
Answer:
61.76 N.
Explanation:
Given the mass of the car, m = 1.60 kg.
The speed of the car, v = 12.0 m/s.
The radius of the circle, r = 5 m.
As car is moving in circular motion, so net force ( normal force + weight of the car) is equal to centripetal force enables the car to reamins in circular path.
Let N is the normal force.
So, 
Now substitute the given values, we get
N = 61.76 N.
Thus, the magnitude ofthe normal force exerted on the car by the walls is 61.76 N.
<span>The speed of the roller coaster when it has to start a similar identical hill the speed would be exactly the same that is 6.0 m/s. And the fact that there is an absence of both friction and air resistance helps us get to this conclusion that it is same as in the previous case.</span>
