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Darina [25.2K]
3 years ago
7

Energy that does not involve the large-scale motion or the position of objects in a system is called a. potential energy. b. mec

hanical energy. c. nonmechanical energy. d. conserved energy.
Physics
2 answers:
docker41 [41]3 years ago
4 0

Answer:

C

Explanation:

Kamila [148]3 years ago
3 0

Answer:

the correct answer is C. non mechanical energy  

Explanation: The stored energy resulting from the relative positions of objects in a system. The energy of a moving object due to its motion. The sum of the kinetic and potential energy of large-scale objects in a system. Energy that lies at the level of atoms and that does not affect motion on a large scale.

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Descibe the real-world examples of Newton's third lawthat were idenified in "Applications of Newton's Laws."
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A horse pulls a cart, a person walks on the ground

Explanation:

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Which two types of air masses would likely form a subtropical jet stream?
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The exact location of the 'subtropical-jet stream' is located at the North phase of 30 Degrees and the reason behind this is due to the variation of air which lies on the region of mid-altitude and warmer equatorial air. the correct answer would be Cool and Warm air masses meeting near the equator.
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What is the most likely effect on the life of a plant if a student cuts it’s flowers?
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PLEASE HELP WITH THIS QUESTION WILL GIVE BRAINLIST TO BEST ANSWER
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The net force is 12 N to the left.
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2 years ago
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A circular cross section, d = 25 mm, experiences a torque load, T = 25 N·m, and a shear force, V = 85 kN. Calculate the shear st
Maru [420]

Answer:

The correct answer is 231 Mpa i.e option a.

Explanation:

using the equation of torsion we Have

\frac{T}{I_{p}}=\frac{\tau }{r}\\\\\therefore \tau =\frac{T}{I_{p}}\times r

where,

\tau= shear stress at a distance 'r' from the center

T = is the applied torque

I_{p} = polar moment of inertia of the section

r = radial distance from the center

Thus we can see that if a point is located at center i.e r = 0 there will be no shearing stresses at the center due to torque.

We know that in case of a circular section the maximum shearing stresses due to a shear force occurs at the center and equals

\tau _{max}=\frac{4}{3}\times \frac{V}{A}

Applying values we get

\tau _{max}=\frac{4}{3}\times \frac{85\times 10^{3}}{0.25\times \pi \times (25\times 10^{-3})^{2}}\\\\\therefore \tau _{max}=230.88Mpa\approx 231Mpa

3 0
3 years ago
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