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erik [133]
2 years ago
6

If 11.87 grams of sand (SiO2) were contained in the mixture, how many atoms of oxygen were in the mixture?

Chemistry
1 answer:
ozzi2 years ago
6 0

Answer:

2.38x10²³ atoms oxygen

Explanation:

To solve this question we need to convert the mass of sand to moles using its molar mass (Molar mass SiO₂ = 60.08g/mol). Twice these moles are the moles of Oxygen and using Avogadro's number we can find the amount of atoms of Oxygen in the mixture:

<em>Moles SiO₂:</em>

11.87g * (1mol / 60.08g) = 0.1976moles SiO₂

<em>Moles Oxygen:</em>

0.1976moles SiO₂* 2 = 0.3951moles oxygen

<em>Atoms oxygen:</em>

0.3951moles oxygen * (6.022x10²³atoms / 1mol O₂) =

<h3>2.38x10²³ atoms oxygen</h3>
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Answer:

Intermolecular forces are the forces of attraction or repulsion which act between neighboring particles (atoms, molecules, or ions ). These forces are weak compared to the intramolecular forces, such as the covalent or ionic bonds between atoms in a molecule.

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Intermolecular forces are important because they determine the physical properties of substances. Many of the life-sustaining properties of water such as its high heat capacity are a result of the hydrogen bonding capabilities it has and are thus due to intermolecular forces.

4 0
2 years ago
What is the ph of 0.1 m naoh solution??
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7 0
3 years ago
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3 0
3 years ago
The molarity of concentrated acetic acid is 17.45 M. When acetic acid is diluted in water it is commonly called vinegar with a m
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7 0
2 years ago
What would the molecular formula be if lithium and sulfur reacted to form a neutral compound?
skad [1K]

Answer:

D, Li2S

Explanation:

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