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Arte-miy333 [17]
3 years ago
11

A free-falling projectile is launched from the ground and has a hangtime of 6 seconds before hitting the ground. How high did it

go?
Physics
1 answer:
grandymaker [24]3 years ago
7 0

1A)  

x=v0x*t=v0cosθ*t  

x=52co31*3.2=142.6 m  

1B)  

y0=1/2gt^2-v0y*t=1/2gt^2-v0sinθt  

y=0.5*9.8*3.2^2-52*sin31*3,2=23.4 m  

2A)  

x=2v0^2sin(2θ)/g  

v0=[xg/2sin(2θ)]^1/2=14.4 m/s  

the initial speed relative to the ground is  

v=v0-4.4=10 m/s  

2B)  

fly time is  

t=2voy/g  

t=2*14.4/9.8=2.94  

2C)  

mgy=1/2mv0y^2  

y=v0y^2/(2g)=10.58 m

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6 0
3 years ago
Find equailent resistance​
vovikov84 [41]

Answer:

0.71ohms

Explanation:

AC and CB are in series hence the total resistance is 3+2=5ohms

AD and DB are in series hence the total resistance is 3+2=5ohms

These resistances are parallel to resistance AB

Let the equivalent resistance be R.

For resistances in parallel

Hence the total resistances are:

5//1//5

1/R =1/5 + 1/1 +1/5 = 1+5+1 /5 = 7/5

Hence the total resistance is R= 1/ 7/5 = 1×5/7= 5/7=0.71ohms

4 0
3 years ago
A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the
Law Incorporation [45]

Answer:

y and length is directly relation

Explanation:

Given data

A single-slit diffraction pattern is formed on a distant scree

angles involved = small

to find out

what factor will the width of the central bright spot on the screen change

solution

we know that  for single slit screen formula is

mass ƛ /area = sin θ and y/L = sinθ

so we can say mass ƛ /area =  y/L

and y = mass length  ƛ / area       .................1

in equation 1 here we can see y and length is directly relation so we can say from equation 1 that  the width of the central bright spot on the screen change if the distance from the slit to the screen is doubled

8 0
3 years ago
A 8.3 resistor and a 5.4 resistor are connected in series with an emf source. The potential difference across the 5.4 resistor i
WINSTONCH [101]

Answer:

The potential difference across the source is 30.45 V.

Explanation:

In this setup we have a voltage divider, we were given the voltage difference on one of the resistors, we know that the difference pottential from the source in this case is the sum of the voltage in each individual resistor, so we can use the following equation to solve this problem:

V_resistor5.4 = (V_source)*(R_5.4)/(R_5.4+R_8.3)

V_source = (V_resistor5.4)*(R_5.4+R_8.3)/(R_5.4)

V_source = (12)*(5.4+8.3)/5.4

V_source = (12)*(13.7)/5.4 = 30.45 V

he potential difference across the source is 30.45 V.

6 0
3 years ago
People can stay informed of weather events by listening to weather updates on the radio. True or False
Cloud [144]

Answer:

the answer is true

Explanation:

true

6 0
4 years ago
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