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frosja888 [35]
3 years ago
11

Please solve number 5!! I’ll mark most brainliest!

Chemistry
2 answers:
sweet-ann [11.9K]3 years ago
7 0
D. 5.25 ml
Jejsjsnxnnsnsbdbbdbdbd
wel3 years ago
6 0

Answer: 5.248

Explanation: 0.53/0.1010 = 5.24752475248, and round to the thousandths.

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If an object is moving right at 10 N and a force is applied from the left at 8N, what is the net force on the object?
ryzh [129]

Answer:

If an object is moving at a constant speed in a constant rightward direction, then the acceleration is zero and the net force must be zero.

5 0
3 years ago
A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu
OLEGan [10]

Answer: The final temperature of nickel and water is  25.2^{o}C.

Explanation:

The given data is as follows.

   Mass of water, m = 55.0 g,

  Initial temp, (t_{i}) = 23^{o}C,      

  Final temp, (t_{f}) = ?,

  Specific heat of water = 4.184 J/g^{o}C,      

Now, we will calculate the heat energy as follows.

           q = mS \Delta t

              = 55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)

Also,

    mass of Ni, m = 15.0 g,

   Initial temperature, t_{i} = 100^{o}C,

   Final temperature, t_{f} = ?

 Specific heat of nickel = 0.444 J/g^{o}C

Hence, we will calculate the heat energy as follows.

          q = mS \Delta t

             = 15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)      

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

              q_{water}(gain) = -q_{alloy}(lost)

55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C) = -(15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C))

       t_{f} = \frac{25.9^{o}C}{1.029}

                 = 25.2^{o}C

Thus, we can conclude that the final temperature of nickel and water is  25.2^{o}C.

6 0
3 years ago
What is SEAgel help plz
DanielleElmas [232]

SEAgel (Safe Emulsion Agar gel) is one of a class of high-tech foam materials known as aerogels.

5 0
3 years ago
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The pressure of a basketball is 412 mmHg. How many kPa is that equal to?
pychu [463]

Answer:

d. 54.9 kPa

Explanation:

mmHg and Pa are units of pressure used in chemistry principally in the study of gases. 1mmHg is equal to 133.322Pa. 412mmHg are:

412 mmHg * (133.322Pa / 1mmHg) = 54929 Pa

The prefix K (Kilo) represents one thousand of the determined unit.

54929Pa are:

54929Pa * (1KPa / 1000Pa) = 54.9kPa

Right answer is:

<h3>d. 54.9 kPa </h3>

3 0
3 years ago
What is the formula for water​
NARA [144]

Answer:

H2O

Explanation:

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