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frosja888 [35]
3 years ago
11

Please solve number 5!! I’ll mark most brainliest!

Chemistry
2 answers:
sweet-ann [11.9K]3 years ago
7 0
D. 5.25 ml
Jejsjsnxnnsnsbdbbdbdbd
wel3 years ago
6 0

Answer: 5.248

Explanation: 0.53/0.1010 = 5.24752475248, and round to the thousandths.

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The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
2 years ago
can someone solve me some papers I don't have time and I need to submit today please I will make you brilliant ​
dem82 [27]

Answer:

submit the papers onto this platform and we will try to help out.

6 0
3 years ago
Elemental sulfur is one of the products of the gas-phase reaction of nitric acid and hydrogen sulfide. The other
Goshia [24]

Answer:

The manufacturing processes for liquefied petroleum gas are designed so that the majority, if not all, of the sulfur compounds are removed. The total sulfur level is therefore considerably lower than for other crude oil-based fuels and a maximum limit for sulfur content helps to define the product more completely. The sulfur compounds that are mainly responsible for corrosion are hydrogen sulfide, carbonyl sulfide and, sometimes, elemental sulfur. Hydrogen sulfide and mercaptans have distinctive unpleasant odors. A control of the total sulfur content, hydrogen sulfide and mercaptans ensures that the product is not corrosive or nauseating. Stipulating a satisfactory copper strip test further ensures the control of the corrosion.

8 0
2 years ago
How many millimeters are there in 5.12 x 10^5
Anton [14]

Answer:

5.12x10¹¹ millimeters

Explanation:

Milli is a prefix used in science and engineering to decribe the number as the exponent x10⁻³. In the prefix kilo, the number is at the exponent x10³.

5.12x10⁵ kilometers are:

5.12x10⁵ kilometers * (1000m / 1km) = 5.12x10⁸ meters

5.12x10² meters * (1m / 1000millimeters) = 5.12x10¹¹ millimeters

8 0
3 years ago
If a flask containing one liter of water was poured into 1,000 small cubes, then each cube would contain:
erastova [34]
Every cube would contain 1 milliliter of water, or .01 liter
7 0
3 years ago
Read 2 more answers
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