Question

Unpolarized light is passed through an optical filter that is oriented in the vertical direction. 1) If the incident intensity of the light is 90 W/m2, what is the intensity of the light that emerges from the filter? (Express your answer to two significant figures.)

Answer 1

Answer:

45 W/m^2

Explanation:

Intensity of light, Io = 90 W/m^2

According to the law of Malus

$I=I_{0}Cos^{2}\theta$

The average value of Cos^θ is half

So, I = Io/2

I = 90 /2

I = 45 W/m^2