Explanation:
We need convert the velocities first to m/s and we get the following:
v2 = 21 km/hr = 5.8 m/s
v1 = 11 km/hr = 3.1 m/s
We need to find the mass of the car also for later use do using the work-energy theorem:
6.0x10^3 J = (0.5) m [(5.8)^2 - (3.1)^2]
or
m = 499.4 kg
Now we determine work needed delta W to change its velocity from 21 km/hr to 33 km/hr
v2 = 33 km/hr = 9.2 m/s
v1 = 21 km/hr = 5.8 m/s
delta W = (0.5)(499.4)[(9.2)^2 - (5.8)^2]
= 1.3 x 10^4 J
Frequency= speed/ wavelength
f= 3.0 × 10^8 m/s/ <span>3.5 × 10^-9 m
=8.57x10^16
The answer is letter </span><span>B. 8.57 × 10^16 Hz.</span>
Answer:
0.629 m
Explanation:
For destructive interference we have the case
m = 1,2,3.....
Frequency is given by
Wavelength
The angle
The width is
The width of the hole is 0.629 m
For destructive interference
The angles are