Answer:
kE=0.0735 J
Explanation:
Given that
Radius ,R=10 cm = 0.1 m
Mass ,m= 3 kg
Angular speed ,ω = 3.5 rad/s
We know that moment of inertia for solid sphere given as
Kinetic energy
Now by putting the values
kE=0.0735 J
Therefore the kinetic energy will be 0.0735 J
Generator bc. It makes light
The density is
Explanation:
The problem is asking to find the density of the object.
The density of an object is given by:
where
m is the mass of the object
V is its volume
For the object in this problem, we have:
m = 35 g (mass)
(volume)
Substituting , we find the density:
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Answer:
100°C
Explanation:
The heat gained by the ice equals the heat lost by the steam, so the total heat transfer equals 0.
Heat lost by the steam as it cools to 100°C:
q = mCΔT
q = (3 kg) (2.00 kJ/kg/K) (100°C − 120°C)
q = -120 kJ
Total heat so far is negative.
Heat lost by the steam as it condenses:
q = -mL
q = -(3 kg) (2256 kJ/kg)
q = -6768 kJ
Heat absorbed by the ice as it warms to 0°C:
q = mCΔT
q = (6 kg) (2.11 kJ/kg/K) (0°C − (-40°C))
q = 506.4 kJ
Heat absorbed by the ice as it melts:
q = mL
q = (6 kg) (335 kJ/kg)
q = 2010 kJ
Heat absorbed by the water as it warms to 100°C:
q = mCΔT
q = (6 kg) (4.18 kJ/kg/K) (100°C − 0°C)
q = 2508 kJ
The total heat absorbed by the ice by heating it to 100°C is 5024.4 kJ.
If the steam is fully condensed, it loses a total of -6888 kJ.
Therefore, the steam does not fully condense. The equilibrium temperature is therefore 100°C
Answer:
18kcal
Explanation:
Melting enthalpy of water: 80 cal/g
The melting enthalpy discribes how much heat is needed to melt a substance. So you get the heat by multiplying the mass of your substance with its melting enthalpy.
225g*18cal/g=18000cal=18kcal