Question

A platform and a weight totaling 900 N is held in position by a vertical water jet of 5 cm diameter. Determine the velocity of the jet.

Answer 1

Answer:

v = 21.409 m/s

Explanation:

Given data:

Total weight of the platform and weight together, W = 900 N

Diameter of the water jet = 5 cm = 0.05 m

Now,

the force exerted by the water jet is balancing the platform

also,

Force exerted by the water jet = ρAv²

where,

ρ is the density of the water = 1000 kg/m³

A is the area of the outlet of the jet = $\frac{\pi}{4}d^2=\frac{\pi}{4}(0.05)^2$

or

A = 0.00196 m²

v is the velocity of the jet

thus,

W = ρAv²

or

900 = 1000 × 0.00196 × v²

or

v = 21.409 m/s

Hence, the velocity of the jet is 21.409 m/s