1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kupik [55]
3 years ago
9

Which of the following best describes how an electron moves when it absorbs or releases exact amounts of energy?

Chemistry
2 answers:
const2013 [10]3 years ago
4 0

Answer: The correct option is B.

Explanation: As the electron moves from lower energy level to higher energy level, it absorbs some amount of energy. When the electron returns back from this higher energy level to the lower energy level, it emits the exact  amount of energy it has absorbed.

As every orbital has its characteristic energy value, whenever electrons absorb or emit energy, they move to different energy level that is they occupy different orbitals and hence we can say that the electron moves between orbital levels.

Brrunno [24]3 years ago
3 0
B.The electron moves between orbital levels.
You might be interested in
The isotopes K-37 and K-42 have the same
Masteriza [31]

Answer:

the same number of protons

Explanation:

5 0
3 years ago
Read 2 more answers
About the instruction that marko gave to hinano
Elden [556K]

Answer: he gave him a map of somewhere

Explanation:

3 0
2 years ago
The transfer of energy by waves is also known as _______
Verdich [7]

Answer:

wave

Explanation:

'Wave' is a common term for a number of different ways in which energy is transferred: In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields.

i hope this helps and your welcom

5 0
3 years ago
Calculate the activity coefficients for the following conditions:
uysha [10]

<u>Answer:</u>

<u>For a:</u> The activity coefficient of copper ions is 0.676

<u>For b:</u> The activity coefficient of potassium ions is 0.851

<u>For c:</u> The activity coefficient of potassium ions is 0.794

<u>Explanation:</u>

To calculate the activity coefficient of an ion, we use the equation given by Debye and Huckel, which is:

-\log\gamma_i=\frac{0.51\times Z_i^2\times \sqrt{\mu}}{1+(3.3\times \alpha _i\times \sqrt{\mu})}       ........(1)

where,

\gamma_i = activity coefficient of ion

Z_i = charge of the ion

\mu = ionic strength of solution

\alpha _i = diameter of the ion in nm

To calculate the ionic strength, we use the equation:

\mu=\frac{1}{2}\sum_{i=1}^n(C_iZ_i^2)        ......(2)

where,

C_i = concentration of i-th ions

Z_i = charge of i-th ions

  • <u>For a:</u>

We are given:

0.01 M NaCl solution:

Calculating the ionic strength by using equation 2:

C_{Na^+}=0.01M\\Z_{Na^+}=+1\\C_{Cl^-}=0.01M\\Z_{Cl^-}=-1

Putting values in equation 2, we get:

\mu=\frac{1}{2}[(0.01\times (+1)^2)+(0.01\times (-1)^2)]\\\\\mu=0.01M

Now, calculating the activity coefficient of Cu^{2+} ion in the solution by using equation 1:

Z_{Cu^{2+}}=2+\\\alpha_{Cu^{2+}}=0.6\text{  (known)}\\\mu=0.01M

Putting values in equation 1, we get:

-\log\gamma_{Cu^{2+}}=\frac{0.51\times (+2)^2\times \sqrt{0.01}}{1+(3.3\times 0.6\times \sqrt{0.01})}\\\\-\log\gamma_{Cu^{2+}}=0.17\\\\\gamma_{Cu^{2+}}=10^{-0.17}\\\\\gamma_{Cu^{2+}}=0.676

Hence, the activity coefficient of copper ions is 0.676

  • <u>For b:</u>

We are given:

0.025 M HCl solution:

Calculating the ionic strength by using equation 2:

C_{H^+}=0.025M\\Z_{H^+}=+1\\C_{Cl^-}=0.025M\\Z_{Cl^-}=-1

Putting values in equation 2, we get:

\mu=\frac{1}{2}[(0.025\times (+1)^2)+(0.025\times (-1)^2)]\\\\\mu=0.025M

Now, calculating the activity coefficient of K^{+} ion in the solution by using equation 1:

Z_{K^{+}}=+1\\\alpha_{K^{+}}=0.3\text{  (known)}\\\mu=0.025M

Putting values in equation 1, we get:

-\log\gamma_{K^{+}}=\frac{0.51\times (+1)^2\times \sqrt{0.025}}{1+(3.3\times 0.3\times \sqrt{0.025})}\\\\-\log\gamma_{K^{+}}=0.070\\\\\gamma_{K^{+}}=10^{-0.070}\\\\\gamma_{K^{+}}=0.851

Hence, the activity coefficient of potassium ions is 0.851

  • <u>For c:</u>

We are given:

0.02 M K_2SO_4 solution:

Calculating the ionic strength by using equation 2:

C_{K^+}=(2\times 0.02)=0.04M\\Z_{K^+}=+1\\C_{SO_4^{2-}}=0.02M\\Z_{SO_4^{2-}}=-2

Putting values in equation 2, we get:

\mu=\frac{1}{2}[(0.04\times (+1)^2)+(0.02\times (-2)^2)]\\\\\mu=0.06M

Now, calculating the activity coefficient of K^{+} ion in the solution by using equation 1:

Z_{K^{+}}=+1\\\alpha_{K^{+}}=0.3\text{  (known)}\\\mu=0.06M

Putting values in equation 1, we get:

-\log\gamma_{K^{+}}=\frac{0.51\times (+1)^2\times \sqrt{0.06}}{1+(3.3\times 0.3\times \sqrt{0.06})}\\\\-\log\gamma_{K^{+}}=0.1\\\\\gamma_{K^{+}}=10^{-0.1}\\\\\gamma_{K^{+}}=0.794

Hence, the activity coefficient of potassium ions is 0.794

6 0
3 years ago
HELP PLZ <br> Calculate the percent composition by mass of iron in Fe(NO3)3
cestrela7 [59]
Hey ik this isn’t a big help but there is a Chem app you can use to get your answers faster rather than waiting for someone to respond. anyways the app is called, ChemCalculator.
5 0
2 years ago
Other questions:
  • What liquid doesn't belong in a science laboratory?
    9·1 answer
  • How would you determine the proper number of significant figures for measurement of a liquid using a graduated cylinder?
    14·1 answer
  • Jamal was riding his bike home at a speed of 12 mph. On his trip out, he had traveled 8 miles away from his house. He has been t
    5·2 answers
  • A fixed amount of gas at 25.0°C occupies a volume of 10.0 L when the pressure is 667 torr. Use Boyle's law to calculate the pres
    9·1 answer
  • What is the difference between the number of electrons in an atom of selenium?
    6·1 answer
  • What is the compound of scI2
    11·1 answer
  • When does the object change direction?
    11·1 answer
  • The conjugate pair for a strong base is -
    14·1 answer
  • Would an Ocean Wave viewed from<br> above appear to be a transverse or<br> longitudinal wave?
    6·1 answer
  • 5.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!