You are measuring an Intensive property
Answer:
0.70 J/g.°C
Explanation:
Step 1: Given data
- Mass of graphite (m): 402 g
- Heat absorbed (Q): 1136 J
- Initial temperature: 26°C
- Specific heat of graphite (c): ?
Step 2: Calculate the specific heat of graphite
We will use the following expression.
Q = c × m × ΔT
c = Q / m × ΔT
c = 1136 J / 402 g × (30°C - 26°C)
c = 0.70 J/g.°C
Answer:
The answer to your question is: $ 35.6
Explanation:
C₆H₁₂N₂O₄Pt
Platinum = 52.5 %
Price = $1047 / troy ounce
cost of platinum = ? of 2 g
1 troy ounce = 480 grains
1 grain = 64.8 mg
Process
Get 52.5 % of 2 g
2 g ----------------- 100 %
x ----------------- 52.5%
x = (52.5 x 2) / 100
x = 1.05 g
1 g --------------------- 1000 mg
1.05 g ---------------- x
x = 1050 mg of Pt
1 grain ---------------- 64.8 mg
x --------------- 1050 mg
x = 16.2 grains
480 grains ---------------- 1 troy ounce
16.2 grains ---------------- x
x = (16.2 x 1) / 480
x = 0.034 troy ounce
$ 1047 ------------------ 1 troy ounce
x ------------------- 0.034
x = (0,034 x 1047) / 1
x = $ 35.6
Answer:
In He2 molecule,
Atomic orbitals available for making Molecular Orbitals are 1s from each Helium. And total number of electrons available are 4.
Molecular Orbitals thus formed are:€1s2€*1s2
It means 2 electrons are in bonding molecular orbitals and 2 are in antibonding molecular orbitals .
Bond Order =Electrons in bonding molecular orbitals - electrons in antibonding molecular orbitals /2
Bond Order =Nb-Na/2
Bond Order =2-2/2=0
Since the bond order is zero so that He2 molecule does not exist.
Explanation:
Answer:
.11 mol
Explanation:
Convert mmHg to atms by dividing by 760. Then multiply 6.3 by the atms and divide by .08206*(273+28) to get mol
