how does a sprinter sprint what is the forward force on a sprinter as she accelerates. where does that force come from
1 answer:
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Answer:
x₂ = 1.33 m
Explanation:
For this exercise we must use the rotational equilibrium condition, where the counterclockwise rotations are positive and the zero of the reference system is placed at the turning point on the wall
Στ = 0
W₁ x₁ - W₂ x₂ = 0
where W₁ is the weight of the woman, W₂ the weight of the table.
Let's find the distances.
Since the table is homogeneous, its center of mass coincides with its geometric center, measured at zero.
x₁ = 2.5 -1.5 = 1 m
The distance of the person is x₂ measured from the turning point, at the point where the board begins to turn the girl must be on the left side so her torque must be negative
x₂ =
let's calculate
x₂ =
x₂ = 1.33 m
Answer:
0.82 m
Explanation:
We are given that
Weight,=225 N
Length,l=5 m
d=1.1 m
We have to find the distance x for which person weighs 385 N walk on the overhanging part of the plank before it just begins to tip.
Half length=
When system in equilibrium then