Answer: 90 kgm/s
Explanation:
The momentum (linear momentum) is given by the following equation:
Where:
is the mass of the skater
is the velocity
In this situation the skater has two values of momentum:
Initial momentum:
Final momentum:
Where:
So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):
Finally:
A 15.75-g<span> piece of iron absorbs 1086.75 </span>joules<span> of </span>heat<span> energy, and its ... </span>How many joules<span> of </span>heat<span> are </span>needed<span> to raise the temperature of 10.0 </span>g<span> of </span>aluminum<span> from 22°C to 55°C, if the specific </span>heat<span> of </span>aluminum<span> is o.90 J/</span>g<span>”C2 .</span>
Explanation:
Internal energy = heat + work
U = Q + W
Since there's no change in volume (rigid walls), W = 0.
U = Q
U = n Cᵥ ΔT
U = (4.0 mol) (2.5 × 8.314 J/mol/K) (354 C − 17 C)
U = 28,000 J
Answer:
The property of the wave marked X is related to the source of the wave
Explanation:
The source of of origin of waves
Electromagnetic wave are waves that consists of varying electric and magnetic field that vibrate perpendicular to each other and to the direction of propagation of the wave and they are therefore transverse waves and transfer energy
Electromagnetic waves originate from the vibration of charged particles that gives off varying electric and magnetic fields
Mechanical waves are defined as waves that require a material medium such as air, water, metal, plastic, stretched leather, or wood to propagate
Mechanical waves originate from vibration of the particles of a medium
Sound waves which is a form of longitudinal mechanical waves that propagates by the vibration of the particles of a given medium about a point parallel to the direction of propagation of the wave.
Answer:
Explanation:
given,
radius of curve = 166 m
angle of the banked road = 11°
mass of car = 736 Kg
speed of the curve = 81 km/h
= 81 x 0.278 = 22.52 m/s
normal force acting on the tires
on tire there will be two force acting on it
first one will be force acting due to weight and the other force acting on the tire is due to centripetal force.