The composition and properties of a(n) _____ are always constant throughout a given sample and from sample to sample

You are 12 miles north of your base camp when you begin walking north at a speed of 2mph. what is your location, relative to you

Leona [35]

Http://www.calculator.net/pace-calculator.html?ctype=distance&ctime=05%3A00%3A00&cdistance=5&cdistanceunit=Miles&cpace=02%3A00%3A00&cpaceunit=tpm&printit=0&x=87&y=24 a pace calculator

4 0

3 years ago

A windmill converts the mechanical energy of wind into ?

sammy [17]

Electric power most likely. It can be a generator for a power plant if needed. Hope this helped. Sorry if it didn't.

7 0

3 years ago

An infant's toy has a 120 g wooden animal hanging from a spring. If pulled down gently, the animal oscillates up and down with a

Morgarella [4.7K]

Answer:

0.37 m

Explanation:

The angular frequency, ω, of a loaded spring is related to the period, T, by

$\omega = \dfrac{2\pi}{T}$

The maximum velocity of the oscillation occurs at the equilibrium point and is given by

$v = \omega A$

A is the amplitude or maximum displacement from the equilibrium.

$v = \dfrac{2\pi A}{T}$

From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,

$v = \dfrac{2\times3.142\times0.25\text{ m}}{0.58\text{ s}} = 2.71 \text{ m/s}$

To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation

$v_f^2 = v_i^2+2ah$

$v_f$ is the final velocity, $v_i$ is the initial velocity (same as v above), a is acceleration of gravity and h is the height.

$h = \dfrac{v_f^2 - v_i^2}{2a}$

$h = \dfrac{0^2 - 2.71^2}{2\times-9.81} = 0.37 \text{ m}$

3 0

3 years ago

Would a measured force of (46.5 0.8 N  ) be in agreement with a theoretically calculated force of (48.4 0.6 N  ) ? Show your w

OverLord2011 [107]

Answer:

A measured force of (46.5 0.8 N  ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N  )

Explanation:

From the question we are told that

Measured force is $F_M = [46.5 \pm 0.8 \ N ]$

Calculated force is $F_c = [48.4 \pm 0.6 \ N ]$

Generally the measured force in interval form is

$46.5 - 0.8 < F_M < 46.5 + 0.8$

=> $45.7 < F_M < 47.3$

Generally the calculated force in interval form is

$48.4 - 0.6 < F_c < 48.4 + 0.6$

=> $47.8 < F_M$

Generally looking both interval we see that they do not intersect at any point Hence

A measured force of (46.5 0.8 N  ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N  )

8 0

2 years ago

What physics principle is used in radar guns to find the speeds of tennis balls and baseballs at sporting events?

Luda [366]

<h2>Answer: Doppler effect </h2>

Explanation:

A radar gun (also known as a Doppler radar) uses the Doppler effect when measuring "return echoes" after having sent a microwave signal (a type of electromagnetic radiation).

In this context the Doppler effect consists of the change in a wave perceived frequency when the emitter of the waves, and the observer move relative to each other.

In the case of radars, a microwave signal is sent to a target (the tennis or baseball in this case) and then is reflected after "hitting" the target, so that the radar system measures this difference between the sent signal and the reflected signal.

6 0

3 years ago