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Taya2010 [7]
3 years ago
12

You are using a diffraction grating with 2230 lines per centimeter. White light passes through it, and the grating spreads the l

ight out into its spectral components. At what angle does green light of wavelength 508 nm appear in second order
Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

The angle of diffraction is 13.09°

Explanation:

Given:

Wavelength of light \lambda = 508 \times 10^{-9} m

Order of diffraction n = 2

No. lines per centimeter N = 2230

First find the grating element,

  d = \frac{1}{N}

  d = 4.484 \times 10^{-6} m

From the formula of diffraction,

  d \sin \theta = n \lambda

    \sin \theta = \frac{2 \lambda}{d}

    \sin \theta = \frac{2 \times 508 \times 10^{-9} }{4.484 \times 10^{-6} }

    \theta = \sin ^{-1} (0.2265)

    \theta = 13.09°

Therefore, the angle of diffraction is 13.09°

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Answer:

v = 11.0 m/s at 198.6° (18.6° south of west)

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Explanation:

I assume you want to find the final velocity and the change in kinetic energy.

Take east to be +x and north to be +y.

Momentum is conserved in the x direction:

(1050 kg) (0 m/s) + (750 kg) (-25.0 m/s) = (1050 kg + 750 kg) vₓ

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Momentum is conserved in the y direction:

(1050 kg) (-6.00 m/s) + (750 kg) (0 m/s) = (1050 kg + 750 kg) vᵧ

vᵧ = -3.50 m/s

The magnitude of the final velocity is:

v² = (-10.4 m/s)² + (-3.50 m/s)²

v = 11.0 m/s

The direction of the final velocity is:

θ = atan(-3.50 m/s / -10.4 m/s)

θ = 198.6°

The initial kinetic energy is:

KE₀ = ½ (1050 kg) (6.00 m/s)² + ½ (750 kg) (25.0 m/s)²

KE₀ = 253,275 J

The final kinetic energy is:

KE = ½ (1800 kg) (11.0 m/s)²

KE = 108,682 J

The change in kinetic energy is:

ΔKE = 108,682 J − 253,275 J

ΔKE ≈ -145,000 J

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Explanation:

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