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Taya2010 [7]
3 years ago
12

You are using a diffraction grating with 2230 lines per centimeter. White light passes through it, and the grating spreads the l

ight out into its spectral components. At what angle does green light of wavelength 508 nm appear in second order
Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

The angle of diffraction is 13.09°

Explanation:

Given:

Wavelength of light \lambda = 508 \times 10^{-9} m

Order of diffraction n = 2

No. lines per centimeter N = 2230

First find the grating element,

  d = \frac{1}{N}

  d = 4.484 \times 10^{-6} m

From the formula of diffraction,

  d \sin \theta = n \lambda

    \sin \theta = \frac{2 \lambda}{d}

    \sin \theta = \frac{2 \times 508 \times 10^{-9} }{4.484 \times 10^{-6} }

    \theta = \sin ^{-1} (0.2265)

    \theta = 13.09°

Therefore, the angle of diffraction is 13.09°

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A 90 kg ice skater moving at 12.0 m/s on the ice encounters a region of roughed up ice with a coefficient of kinetic friction of
balandron [24]

Answer:

The skater covers a distance of <u>15 m</u> before stopping.

Explanation:

Let the distance traveled before stopping be 'd' m.

Given:

Mass of the skater (m) = 90 kg

Initial velocity of the skater (u) = 12.0 m/s

Final velocity of the skater (v) = 0 m/s (Stops finally)

Coefficient of kinetic friction (μ) = 0.490

Acceleration due to gravity (g) = 9.8 m/s²

Now, we know that, from work-energy theorem, the work done by the net force on a body is equal to the change in its kinetic energy.

Here, the net force acting on the skater is only frictional force which acts in the direction opposite to motion.

Frictional force is given as:

f=\mu N

Where, 'N' is the normal force acting on the skater. As there is no vertical motion, N=mg

∴ f=\mu mg=0.490\times 90\times 9.8=432.18\ N

Now, work done by friction is a negative work as friction and displacement are in opposite direction and is given as:

W=-fd=-432.18d

Now, change in kinetic energy is given as:

\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}\times 90(0-12^2)\\\\\Delta K=45\times (-144)=-6480\ J

Therefore, from work-energy theorem,

W=\Delta K\\\\-432.18d=6480\\\\d=\frac{6480}{432.18}\\\\d=14.99\approx 15\ m

Hence, the skater covers a distance of 15 m before stopping.

7 0
3 years ago
Lenses are described as convergent or divergent depending on how they refract light. What is the difference between these two ty
Umnica [9.8K]

Answer:

Explanation:

Convergent lens is the lens which converges the rays of light falling on it. It is thicker at the middle and thinner at the edges. It is also known as convex lens.

Divergent lens is the lens which diverge the rays of light falling on it. It is thinner at the middle and thicker at the edges. It is also called as concave lens.

5 0
3 years ago
50. A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage to 335 kV. The secondar
Sedaia [141]

Answer:

Explanation:

a )  The transformer steps  up  the voltage from 12000 V  to 335000 V . Voltage in primary is 12000 V and in the secondary it is 335000 V in old transformer

If n₁ be no of turns in primary coil and n₂ be no of turns in secondary coils

the formula is

n₂ / n₁ = voltage in secondry / voltage in primary

n₂ / n₁ = 335000 / 12000

ratio of turns  in old transformer

= 27.9

ratio of turns  in new transformer

n₃ / n₁ = 750 / 12 ( n₃ is no of turns in the  secondary of new transformer )

= 62.5

T he ratio of turns in the new secondary compared with the old secondary

n₃ / n₂ = 62.5 / 27.9

= 2.24

b ) Current in secondary / current in primary

= turns in primary / turns in secondary

current output ratio of old

= Current in secondary / current in primary

= n₁ / n₂

= 12 / 335

= .03582

current output ratio of new

= Current in secondary / current in primary

= n₁ / n₃

= 12 / 750  

= .016

The ratio of new current output to old output (at 335 kV) for the same power

= .016 / .03582

= .4466

c ) power loss in new

=  (current in secondary )² x resistance of secondary

=( .016 x current in primary )² x R

= 2.56 X 10⁻⁴ X ( current in primary )² x R

power loss in old  

=  (current in secondary )² x resistance of secondary

=( .03582 x current in primary )² x R

= 12.83 X 10⁻⁴ X ( current in primary )² x R

ratio of new line power loss to old

= 2.56 / 12.83

= .199

7 0
3 years ago
Why are bridges declared unsafe after a long use​
lina2011 [118]

After it's long use, the bridge continuously undergoes through alternating strains. in result, the elastic strength of the bridge gets reduced. while the process goes on the bridge makes elastic fatigue and a permanent change happens which makes it collapse which is the reason why bridges are declared unsafe after a long use​ :)

8 0
3 years ago
Explain the energy transformations that occur when breaking in a hybrid<br> vehicle.
KatRina [158]

it occur kinetic energy

when breaking in a hybrid

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hope it helps

8 0
3 years ago
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