The complete question is;

In an amusement park ride called The Roundup, passengers stand inside a 16-m-diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane.

Suppose the ring rotates once every 4.30 s . If a rider's mass is 53.0 kg , with how much force does the ring push on her at the top of the ride?

Answer:

F_top = 385.36 N

Explanation:

We are given;

mass;m = 52 kg

Time;t = 4.3 s

Diameter;d = 16m

So,Radius;r = 16/2 = 8m

The formula for the centrifugal force is given as;

F_c = mω²R

Where;

R = radius

Angular velocity;ω = 2πf

f = frequency = 1/t = 1/4.3 Hz

F_c = 53 × (2π × 1/4.3)² × 8 = 905.29 N.

The force at top would be;

F_top = F_c - mg

F_top = 905.29 - (9.81 × 53) N

F_top = 385.36 N

**Answer:**

**b. Jupiter’s greater gravity has compressed the layers, so they are closer together there.**

**Explanation:**

The value for **Jupiter** mass is **1.8981×10²⁷kg**, while the mass of **Saturn** is **5.6832×10²⁶kg**, so the different layers of clouds in Jupiter will be submitted to a greater gravitational pull because it has a bigger mass, as is established in the law of universal gravitation:

** (1) **

Where **m1** and **m2** are the masses of two objects, **G** is the gravitational constant and **r** is the distance between the two objects.

As it can be seen in equation 1, the gravitational force is directly proportional to the product of the masses of the objects, so if the mass increase the gravitational force will do it too.

For the case of Saturn, it has a lower mass so its layers of clouds will suffer a weaker gravitational pull. That leads to the three clouds being more spacing that the ones of Jupiter.** **

If the moon had twice the diameter with same mass and orbital distance from earth, then the high tides on Earth would be** practically the same**.

<u>**Explanation:**</u>

As the tides occurring in the earth is **mostly due to the gravitational force** of the moon acting on the earth. The distance between the earth and the moon mainly influences high tides. So, tidel force can be termed as directly proportionate to the gravitational forces acting between moon and earth.

As the gravitational forces act on Earth due to the moon will be directly proportionate to the product of masses of Earth and Moon and inversely proportionate to the distance squared (separation between Earth and Moon), due to the universal law of gravitation.

Thus, it can be stated that the **diameter of the moon has no role to play** in the high tides. As it is stated that the mass and distance almost remained the same, and there is only a change in the diameter of the moon, the high tides will not be exhibiting much change. Thus, on earth the high tides would be practically the **same on increasing the diameter **of the Moon.

**Answer: **A gland is an organ which produces and releases substances that perform a specific function in the body.

**Explanation: **<em>A gland is an organ which produces and releases substances that perform a specific function in the body. There are two types of gland. Endocrine glands are ductless glands and release the substances that they make (hormones) directly into the bloodstream.</em>

There is no **temperature change** which drives** heat flow**, thus no **heat **will be released by the water.

<h3>

**Heat released by the water when it freezes**</h3>

The **heat **released by the water when it freezes is calculated as follows;

Q = mcΔФ

where;

- m is mass of water
- c is specific heat capacity of water
- ΔФ is change in temperature = Фf - Фi

**Initial temperature **of water, Фi = 0 °C

when water freezes, the **final temperature**, Фf = 0 °C

Q = 22 x 4200 x (0 - 0)

Q = 0

Since there is no **temperature change** which drives** heat flow**, thus no **heat **will be released by the water.

Learn more about **heat flow** here: brainly.com/question/14437874