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klasskru [66]
3 years ago
7

Find the magnitude of vector A = i - 2j + 3k O V14 10 O4

Physics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Answer:

|A|=\sqrt{1^2+(-2)^2+(3)^2}=3.74

Explanation:

Given that,

Vector A=i-2j+3k............(1)

We need to find the magnitude of vector A. Let us suppose vector in the form of, R = xi + yj + zk. Its magnitude is given by :

|R|=\sqrt{x^2+y^2+z^2}

In equation (1),

x = 1

y = -2

z = 3

So, the magnitude of vector A is given by :

|A|=\sqrt{1^2+(-2)^2+(3)^2}

|A| = 3.74

So, the magnitude of given vector is 3.74. Hence, this is the required solution.

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