Find the magnitude of vector A = i - 2j + 3k O V14 10 O4

Physics

1 answer:

Angelina_Jolie [31]3 years ago

6 0

Answer:

$|A|=\sqrt{1^2+(-2)^2+(3)^2}=3.74$

Explanation:

Given that,

Vector $A=i-2j+3k$ ............(1)

We need to find the magnitude of vector A. Let us suppose vector in the form of, R = xi + yj + zk. Its magnitude is given by :

$|R|=\sqrt{x^2+y^2+z^2}$

In equation (1),

x = 1

y = -2

z = 3

So, the magnitude of vector A is given by :

$|A|=\sqrt{1^2+(-2)^2+(3)^2}$

|A| = 3.74

So, the magnitude of given vector is 3.74. Hence, this is the required solution.

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