Answer:
(a) OPTION E=4
b) option E C sp² + C p
Explanation:
DEGREE OF UNSATURATION = C -H/2 -X/2 +N/2 +1
X IS HALOGENS
5-5/2+1/2+1= 4
b) Ethene comprises of two sp2-hybridized carbon atoms (bound to each other by sigma and two atoms each with hydrogen). The remaining unhybridized carbon p orbitals form a pi bond, giving ethene reactivity
Data:
P (pressure) = 2.3 atm
V (volume) = 120 L
T (temperature) = 340 K
n (number of mols) = ?
R (Gas constant) = 0.082 (atm*L/mol*K)
Formula:

Solving:





C3H6Br2 2 isomers:- bominated allkane
CH3CH2CHBr2 1,1-dibromopropane
<span>CH3CHBrCH2Br 1,2-dibromopropane
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