Answer:
the maximum allowable current is 7302.967 amperl
Explanation:
The computation of the maximum allowable current is shown below;
Force F = mean ÷ 4π 2 I_1 I_2 ÷d × ΔL
200 N = (10)^-7 (2I × I) ÷ 0.08 × 1.5
200 = 3.75 × 10^-6 I^2
I = √200 ÷ √ 3.75 × 10^-6
= 7302.967 amperl
Hence, the maximum allowable current is 7302.967 amperl
Basically we applied the above formula
Answer:
pressure = density x g x height
= 1000 x 10 x 6 Pascal
=60000 Pascal
OR 60 kP
The remote control, and wireless transmissions
Answer:
294 W
Explanation:
Electrical power: This can be defined as the rate at which electrical energy is used or dissipated. The S.I unit of electrical power is Watt(W).
The expression of electrical power is given as,
P = I²R................... Equation 1
Where P = power, I = current, R = Resistance.
Given: I = 7 A, R = 6 Ω
Substitute into equation 1
P = (7)²(6)
P = 294 W.
Hence the power power absorbed by the resistor is 294 W
Answer: 5 m/s^2
Explanation: In order to solve this question we have to use the kinematic equation given by:
Vf= Vo+a*t where V0 is zero.
we know that it takes Vf( 30 m/s) in 6 seconds
so
a=(30 m/s)/6 s= 5 m/s^2