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3 years ago

If the current throught a 6 Ω resistor is 7 A, what is the power absorbed by the resistor? Answer to the nearest 1 W.

Physics

2 answers:

Strike441 [17]3 years ago

5 0

Answer:

290W

Explanation:

The relationship between power (P) absorbed by a resistor, the current (I) flowing through the resistor and the value of resistance is given by;

P = $I^{2}$ x R

This means that the power absorbed by a resistor is the product of the current flowing through it and the value of its resistance.

Given;

I = current flowing = 7A

R = resistance = 6 Ω

Substituting the values of I and R into the equation above gives;

=> P = $7^{2}$ x 6

=> P = 49 x 6

=> P = 294W

Converting this to the nearest 1W gives 290W.

<em>Therefore, the power absorbed by the resistor is 290W</em>

Stells [14]3 years ago

3 0

Answer:

294 W

Explanation:

Electrical power: This can be defined as the rate at which electrical energy is used or dissipated. The S.I unit of electrical power is Watt(W).

The expression of electrical power is given as,

P = I²R................... Equation 1

Where P = power, I = current, R = Resistance.

Given: I = 7 A, R = 6 Ω

Substitute into equation 1

P = (7)²(6)

P = 294 W.

Hence the power power absorbed by the resistor is 294 W

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