Answer:
Object D
Explanation:
Use Newton's Second Law to determine the acceleration that each object has.
The force applied in both cases is 50 N, but the mass for object C and object D is different.
Let's start with object C first:
- F = ma
- 50 N = 10 kg · a
- 50 = 10a
- 5 = a
The acceleration object C undergoes is 5 m/s².
Now let's calculate object D next:
- F = ma
- 50 N = 2 kg * a
- 50 = 2a
- 25 = a
The acceleration object D undergoes is 25 m/s².
Object D has greater acceleration because it has a smaller mass. The object with a smaller mass will accelerate more in order to satisfy Newton's 2nd Law.
Answer:
The answer to the question is
The object would fall 57.625 m in the first 5 seconds
Explanation:
To solve the question, we note that
the height of fall = 490 ft = 149.352 m
Time to touch the ground = 7 seconds
We are required to find out how far the object falls in the first 5 seconds
We apply the relation
S = u·t + 0.5×g·t ² = We then have
149.352 = U×7+0.5*9.81*49 From where u = -13 m/s
Therefore to find how far it falls in the first 5 seconds, we have
-13*5 + 0.5*9.81*25 = 57.625 m
It is called condensation. Hope this helped!
When soccer players run they are using friction to propell themselves
