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Brut [27]
3 years ago
11

Which is longer, 10 cm or .01 m?

Physics
1 answer:
motikmotik3 years ago
6 0

Answer:

They´re the same.

Explanation:

Someone deleted my answer. And my brainly is gone..

Have a good night ma´am/sir.

Be safe!

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A Parachutist with a camera, with descending at a speed of 12.5m/s, releases, the camera at an altitude of 64.3m. What is the ma
jonny [76]

Given :

Initial velocity, u = 12.5 m/s.

Height of camera, h = 64.3 m.

Acceleration due to gravity, g = 9.8 m/s².

To Find :

How long does it take the camera to reach the ground.

Solution :

By equation of motion :

h = ut+\dfrac{gt^2}{2}

Putting all given values, we get :

12.5t+\dfrac{9.8t^2}{2}=64.3\\\\4.9t^2+12.5t=64.3

t = 2.56  and t = −5.116.

Since, time cannot be negative.

t = 2.56 s.

Therefore, time taken is 2.56 s.

Hence, this is the required solution.

7 0
3 years ago
A mass of 5kg starts from rest and pulls down vertically on a string wound around a disk-shaped, massive pulley. The mass of the
bekas [8.4K]

Answer:

1.98 m/s

Explanation:

To solve this, we would be using the law of conservation of energy, i.e total initial energy is equal to total final energy.

E(i) = E(f)

mgh = ½Iw² + ½mv²

Recall, v = wr, thus, w = v/r

Also, I = ½mr²

I = 0.5 * 5 * 2²

I = 10 kgm²

Remember,

mgh = ½Iw² + ½mv²

Substituting w for v/r, we have

mgh = ½I(v/r)² + ½mv²

Now, putting the values in the equation, we have

5 * 9.8 * 0.3 = ½ * 10 * (v/2)² + ½ * 5 * v²

14.7 = 1.25 v² + 2.5 v²

14.7 = 3.75 v²

v² = 14.7/3.75

v² = 3.92

v = √3.92

v = 1.98 m/s

Thus, the speed is 1.98 m/s

5 0
3 years ago
Why do we add the masses together after that inelastic collision?
fomenos

Answer:An inelastic collision is one in which the internal kinetic energy changes (it is not conserved). A collision in which the objects stick together is sometimes called perfectly inelastic because it reduces internal kinetic energy more than does any other type of inelastic collision.People sometimes think that objects must stick together in an inelastic collision. However, objects only stick together during a perfectly inelastic collision. Objects may also bounce off each other or explode apart, and the collision is still considered inelastic as long as kinetic energy is not conserved.

hope this helps have a nice day❤️

Explanation:

5 0
3 years ago
Can yall help me?
IceJOKER [234]

Explanation:

Ohm's law describes the relationship between voltage, current, and resistance.

V = IR

where V is voltage, I is current, and R is resistance.

A. At the original voltage:

V₁ = I₁ R₁

When the voltage is doubled and resistance stays the same:

2V₁ = I₁' R₁

Dividing the two equations:

2V₁ / V₁ = (I₁' / I₁) (R₁ / R₁)

2 = I₁' / I₁

So the new current is double the original current.

B. At the original voltage and resistance:

V₂ = I₂ R₂

When both the voltage and resistance are increased by a factor of 2:

2V₂ = I₂' (2R₂)

Dividing the two equations:

(2V₂ / V₂) = (I₂' / I₂) (2R₂ / R₂)

2 = (I₂' / I₂) (2)

1 = I₂' / I₂

So the new current is the same as the original current.

3 0
3 years ago
It takes 200 J of work to compress quasi-statically 0.40 mol of an ideal gas to one-fourth its original volume. Calculate the te
mario62 [17]

Answer : The temperature of the gas is, 43.4 K

Explanation :

The expression used for work done will be,

w=-nRT\ln (\frac{V_2}{V_1})

where,

w = work done = 200 J

n = number of moles of gas  = 0.40 mol

R = gas constant = 8.314 J/mole K

T = temperature of gas  = ?

V_1 = initial volume of gas  = X

V_2 = final volume of gas  = \frac{X}{4}

Now put all the given values in the above formula, we get :

200J=-0.40mol\times 8.314J/moleK\times T\times \ln (\frac{(\frac{X}{4})}{X})

T=43.4K

Thus, the temperature of the gas is, 43.4 K

3 0
4 years ago
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