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3 years ago

Compare and contrast continuous spectrum and emission spectrum

1 answer:

5 0

the continuous spectrum of white light only deals with the frequencies and wavelengths of colors associated with the rainbow. and the emission spectrum is I think deals with the colors, frequencies, and wavelengths that are released by a particular atom.

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A flask of fixed volume contains 1.00 mole of gaseous carbon dioxide and 88.0 g of solid carbon dioxide. The original pressure a

Ymorist [56]

Answer:275K

Explanation:

5 0

3 years ago

What is the molality of impurities in thesolvent? If the impurity is largely hexachloroethane, C2Cl6, how many grams of this imp

Contact [7]

Answer:

a) grams of this impurity per kg of CCl4 = 3.416 g/kg of solvent.

b) mass purity % = 99.66%

Explanation:

Given, the freezing point of pure CCl₄ = - 23°C

Presence of impurities lowers the freezing point to - 23.43°C

The freezing point depression constant, Kբ = 29.8°C/m

The lowered freezing point is related to all the parameters through the relation

ΔT = i Kբ × m

where ΔT is the lowered freezing point, that is, the difference between freezing point of pure substance (T⁰) and freezing point of substance with impurities (T).

i = Van't Hoff factor which measures how much the impurities influence/affect colligative properties (such as freezing point depression) and for most non-electrolytes like this one, it is = 1

Kբ = The freezing point depression constant = 29.8°C/m

m = Molality = ?

T⁰ - T = i Kբ m

- 23 - (-23.43) = 1 × 29.8 × m

m = 0.43/29.8 = 0.0144 mol/kg

Then, we're told to calculate impurity of the CCl₄

we convert the Molality to (gram of solute)/(kg of solvent) first

Solute = C₂Cl₆

Molar mass = 236.74 g/mol

So, (molality × molar mass) = (gram of solute)/(kg of solvent)

(gram of solute)/(kg of solvent) = 0.0144 × 236.74 = 3.416 (gram of solute)/(kg of solvent)

Mass purity % = (1000 g of pure substance)/(1000 g of pure substance + mass of impurity in 1000 g of pure substance)

1000 g of solvent contains 3.416 grams of impurities

Mass purity % =100% × 1000/(1003.416)

Mass purity % = 99.66 %

5 0

4 years ago

Most minerals are _______ at room temperature.<br><br> solid<br> gas<br> liquid

Tomtit [17]

Answer:

solid

Explanation:

4 0

3 years ago

Read 2 more answers

How many moles are in 98.3 grams of aluminum hydroxide

solong [7]

Answer:

1.260

Explanation:

7 0

3 years ago

Calculate the solubility in g/l of lead (ii) fluoride in water at 25 oc if ksp of pbf2 is 4. 1 x 10-8.

Tems11 [23]

The solubility in g/l of lead (ii) fluoride in water at 25°C if ksp of PbF2 is 4. 1 x 10-8. is 5.3 ×10^(-1).

When PbF₂ dissolves, it dissociates as follows;

PbF₂ --> Pb²⁺ + 2F⁻

If molar solubility of PbF₂ is x, then molar solubility of Pb²⁺ is x and F⁻ is 2x.

ksp is solubility product constant and it can be calculated as follows;

ksp = [Pb²⁺][F⁻]²

ksp = (x)(2x)²

ksp = 4x³

$4_{X} ^{3} = 4.1 * 10^{-8}\\\\ X^{3} = 1.025 * 10^{-8}\\\\ X = 0.092 * 10^{-3}\\ \\X = 2.1 * 10^{-3}$

To calculate solubility in terms of g/L, we have to know the molar mass of PbF₂.

Solubility of PbF₂ is $2.1 * 10^{-3}$ mol/L x 248 g/mol = $5.14 * 10^{-1}$ g/L

Thus, we concluded that the solubility of given solution is 5.14 × 10^(-1). which is approx 5.3 × 10^(-1).Hence option D is the correct option.

Learn more about solubility: brainly.com/question/14366471

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6 0

2 years ago