Answer:
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Answer:
1.67mol/L
Explanation:
Data obtained from the question include:
Mole of solute (K2CO3) = 5.51 moles
Volume of solution = 3.30 L
Molarity =?
Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:
Molarity = mole of solute /Volume of solution
Molarity = 5.51 mol/3.30 L
Molarity = 1.67mol/L
Therefore, the molarity of K2CO3 is 1.67mol/L
Producers such as plants.
Answer:
A. Theoretical yield = 3.51g
B. %yield = 75%
Explanation:
The balanced equation for the reaction is given below:
C2H4 + 3O2 —> 2CO2 + 2H2O
Molar Mass of O2 = 16 x 2 = 32g/mol
Mass of O2 from the balanced equation = 3 x 32 = 96
Molar Mass of H20 = (2x1) + 16 = 18g/mol
Mass of H2O from the balanced equation = 2 x 18 = 36g
A. From the equation,
96g of O2 produced 36g of H2O
Therefore, 9.35g of O2 will produce = (9.35 x 36)/96 = 3.51g of H2O
Therefore,theoretical yield of water (H2O) = 3.51g
B. Theoretical yield = 3.51
Actual yield = 2.63g
%yield =?
%yield = Actual yield/Theoretical yield x 100
%yield = 2.63/3.51
%yield = 75%
