Question

A balloon having an initial temperature of 17.8°C is heated so that the volume doubles while the pressure is kept fixed. What is the new value of the temperature?

Answer 1

Answer:

$T = 308.6 ^0 C$

Explanation:

Here by ideal gas equation we can say

$PV = nRT$

now we know that pressure is kept constant here

so we will have

$V = \frac{nR}{P} T$

since we know that number of moles and pressure is constant here

so we have

$\frac{V_2}{V_1} = \frac{T_2}{T_1}$

now we know that initial temperature is 17.8 degree C

and finally volume is doubled

So we have

$\frac{2V}{V} = \frac{T_2}{(273 + 17.8)}$

so final temperature will be

$T_2 = 581.6 k$

$T_2 = 308.6 ^o C$