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Mademuasel [1]
3 years ago
12

A balloon having an initial temperature of 17.8°C is heated so that the volume doubles while the pressure is kept fixed. What i

s the new value of the temperature?
Physics
1 answer:
Rama09 [41]3 years ago
5 0

Answer:

T = 308.6 ^0 C

Explanation:

Here by ideal gas equation we can say

PV = nRT

now we know that pressure is kept constant here

so we will have

V = \frac{nR}{P} T

since we know that number of moles and pressure is constant here

so we have

\frac{V_2}{V_1} = \frac{T_2}{T_1}

now we know that initial temperature is 17.8 degree C

and finally volume is doubled

So we have

\frac{2V}{V} = \frac{T_2}{(273 + 17.8)}

so final temperature will be

T_2 = 581.6 k

T_2 = 308.6 ^o C

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