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Mademuasel [1]
3 years ago
12

A balloon having an initial temperature of 17.8°C is heated so that the volume doubles while the pressure is kept fixed. What i

s the new value of the temperature?
Physics
1 answer:
Rama09 [41]3 years ago
5 0

Answer:

T = 308.6 ^0 C

Explanation:

Here by ideal gas equation we can say

PV = nRT

now we know that pressure is kept constant here

so we will have

V = \frac{nR}{P} T

since we know that number of moles and pressure is constant here

so we have

\frac{V_2}{V_1} = \frac{T_2}{T_1}

now we know that initial temperature is 17.8 degree C

and finally volume is doubled

So we have

\frac{2V}{V} = \frac{T_2}{(273 + 17.8)}

so final temperature will be

T_2 = 581.6 k

T_2 = 308.6 ^o C

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A high school physics student is sitting in a seat read-
Nataly_w [17]

The equilibrium condition allows finding the result for the force that the chair exerts on the student is:

  • The reaction force that the chair exerts on the student's support is equal to the student's weight.

Newton's second law gives the relationship between force, mass and acceleration of bodies, in the special case that the acceleration is is zero equilibrium condition.

            ∑ F = 0

Where F is the external force.

The free body diagram is a diagram of the forces on bodies without the details of the shape of the body, in the attached we can see a diagram of the forces.

Let's analyze the force on the chair.

            N_{chair} - W_{chair} - W_{student} = 0 \\ \\N_{chair} = W_{chair} + W_{student}

Let's analyze the forces on the student.

          N_{student} - W_{student} = 0  \\N_{student} = W _{student}

           

In conclusion using the equilibrium condition we can find the result for the force that the chair exerts on the student is:

  • The reaction force that the chair exerts on the student's support is equal to the student's weight.

Learn more here: brainly.com/question/18117041

7 0
2 years ago
Which is gerrymandering a problem for the house of representatives but not the senate?
Fudgin [204]

Senators are elected in statewide elections rather than in specific districts. <em>(D)</em>

3 0
3 years ago
The force of Earth's gravity on a capsule in space will lessen as it moves farther away. If the capsule moves to twice its dista
Bess [88]

Answer: One quarter of the force

Explanation:

According to Newton's law of Gravitation, the force F exerted between two bodies of masses m1 and m2  and separated by a distance r  is equal to the product of their masses and inversely proportional to the square of the distance:

F=G\frac{(m1)(m2)}{r^2}    (1)

Where Gis the gravitational constant

This means that the gravity force decreases when the distance between these two bodies increases.

In this context, if the distance between the capsule and the Earth increases twice, the new distance will be 2r.

Substituting this distance in (1):

F=G\frac{(m1)(m2)}{(2r)^2}    (2)

F=G\frac{(m1)(m2)}{4r^2}    

<u>Finally:</u>

F=\frac{1}{4}G\frac{(m1)(m2)}{r^2} >>>This means the force toward Earth becomes one quarter "weaker"

3 0
3 years ago
when the mass of an object is increased it would decrease its acceleration in the force is left alone
mojhsa [17]

Answer:

See the explanation below.

Explanation:

This analysis can be easily deduced by means of Newton's second law which tells us that the sum of the forces or the total force on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = total force [N]

m = mass [kg]

a = acceleration [m/s²]

We must clear the acceleration value.

a=\frac{F}{m}

We see that the term of the mass is in the denominator, so that if the value of the mass is increased the acceleration decreases, since they are inversely proportional.

4 0
3 years ago
Determine the angle of an incline that would yield a constant velocity, given the coefficient of kinetic friction is 0.10.
azamat

Answer:

\theta=5.71^{o}

Explanation:

In order to solve this problem, we mus start by drawing a free body diagram of the given situation (See attached picture).

From the free body diagram we can now do a sum of forces in the x and y direction. Let's start with the y-direction:

\sum F_{y}=0

-W_{y}+N=0

N=W_{y}

so:

N=mgcos(\theta)

now we can go ahead and do a sum of forces in the x-direction:

\sum F_{x}=0

the sum of forces in x is 0 because it's moving at a constant speed.

-f+W_{x}=0

-\mu_{k}N+mg sen(\theta)=0

-\mu_{k}mg cos(\theta)+mg sen(\theta)=0

so now we solve for theta. We can start by factoring mg so we get:

mg(-\mu_{k} cos(\theta)+sen(\theta))=0

we can divide both sides into mg so we get:

-\mu_{k} cos(\theta)+sen(\theta)=0

this tells us that the problem is independent of the mass of the object.

\mu_{k} cos(\theta)=sen(\theta)

we now divide both sides of the equation into cos(\theta) so we get:

\mu_{k}=\frac{sen(\theta)}{cos(\theta)}

\mu_{k}=tan(\theta)

so we now take the inverse function of tan to get:

\theta=tan^{-1}(\mu_{k})

so now we can find our angle:

\theta=tan^{-1}(0.10)

so

\theta=5.71^{o}

8 0
3 years ago
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