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vladimir2022 [97]
4 years ago
5

A truck traveling at 72km/hr runs into a bridge piling and is stopped in .05s. What is the truck’s acceleration?

Physics
1 answer:
Alex787 [66]4 years ago
3 0

Answer:

400m/s²

Explanation:

initial speed=72km/h=20m/s

final speed=0m/s

acceleration=final-initial/time

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Which of the following are decomposition reactions?
zhenek [66]

The 2 decomposition reactions are:

B. K_{2}CO_{3} (s) --> K_{2} O (s) + CO_{2} (g)

C. 2SO_{3} (g) --> 2SO_{2} (g) + O_{2} (g)

Explanation:

Step 1:

A decomposition reaction is one in which a single compound breaks down into two or more products.

Step 2:

Let us examine each reaction if it satisfies the above rule.

A. 2 LiOH +  CO_{2} ---> Li_{2} CO_{3} + H_{2} O

In this reaction we have 2 reactants giving 2 products. Hence this is not a decomposition reaction.

B. K_{2} CO_{3} ---> K_{2} O + CO_{2}

In this reaction a single reactant potassium carbonate gives rise to 2 products Potassium Oxide and carbon-di-oxide. Hence this is a decomposition reaction

C. 2SO_{3} ---> 2SO_{2} + O_{2}

In this reaction a single reactant sulfur tri-oxide gives rise to 2 products sulfur di-oxide and oxygen. Hence this is a decomposition reaction.

D. 2Na + Cl_{2} ---> 2NaCl_{}

In this reaction 2 reactants sodium and chlorine gives rise to a single product sodium chloride. Hence this is not a decomposition reaction.

Step 3:

Answer:

The 2 decomposition reactions are:

B. K_{2} CO_{3} (s) ---> K_{2}O (s) + CO_{2} (g)

C. 2SO_{3} ---> 2SO_{2} + O_{2}

7 0
3 years ago
PLEASE HELP LOL XDDD
Nimfa-mama [501]

Answer:

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Explanation:

3 0
3 years ago
Read 2 more answers
A constant force is exerted for a short distance on a block of mass that is initially at rest on a horizontal frictionless plane
Irina-Kira [14]

Answer:

v

Explanation:

initial speed is 2v

final speed is 3v

increase is v

7 0
3 years ago
Find the work done by the force ​F = xyi +(y-x)j over the straight line from​ (-1,1)to (3,-3). The amount of work done is ___?
dalvyx [7]

Answer:

amount of work done isW  =  \frac{-4}{3}      

Explanation:

Formula for work done by force field

W = \int F. dr = \int_{t_o}^{t_1} f(r(t)) r'(t) dt

where

r(t) is parametrization of line

as it is straight line so

r(t) = 1- t) r_o + tr_1   0 \leq t \leq 1

thus,

r(t) = (1-t)(-1,1) + t(3,-3)

    = (-1+t,1-t) + (3t - 3t)

   = (-1+t +3t, 1-t-3t)

r(t) = (4t -1, 1- 4t)

r'(t) = (4,-4)

putting value in above integral

\int_{0}^{1} ((4t -1,1-4t)). (4,4) dt = \int_{0}^{1} (-(4t -1)^2 , 2-8t).(4,-4) dt

                                                  = \int_{0}^{1} (-16 t^2 + 8t -1,2-8t) .(4,-4) dt

                                                  =\int_{0}^{1} (4(-16t^2 +8t -1) -4(2-8t)) dt

                                                   = 4[ -16 \frac{t^3}{3} + 16\frac{t^2}{2} - 3t]_{0}^{1}

\int_{0}^{1} ((4t -1,1-4t)). (4,4) dt = \frac{-4}{3}                                                        

3 0
4 years ago
What happens to the chemical bonds during energy exchange?
anygoal [31]

In chemical reactions, chemical bonds are broken and reformed, and release their excess bond energy

8 0
3 years ago
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