1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
algol13
3 years ago
15

What type of reaction is KOH + H2SO4

Chemistry
2 answers:
lakkis [162]3 years ago
6 0
What type of reaction is KOH + K2SO4?
Neutralization, because the acid and base react to form both salt and water. 
Hope I helped!(:
Lady_Fox [76]3 years ago
4 0
<span> neutralization, cause the acid and base react</span>
You might be interested in
Need help !!!!! ASAP
Ksivusya [100]
<h2>Hello!</h2>

The answer is:

We have that there were produced 0.120 moles of CO_{2}

n=0.120mol

<h2>Why?</h2>

We are asked to calculate the number of moles of the given gas, also, we  are given the volume, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.

The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

PV=nRT

Where,

P is the pressure of the gas.

V is the volume of the gas.

n is the number of moles of the gas.

T is the absolute temperature of the gas (Kelvin).

R is the ideal gas constant (to work with pressure in mmHg), which is equal to:

R=62.363\frac{mmHg.L}{mol.K}

We must remember that the The Ideal Gas Law equation works with absolute temperatures (K), so, if we are given relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert it to Kelvin before we proceed to work with the equation.

We can convert from Celsius degrees to Kelvin using the following formula:

Temperature(K)=Temperature(C\°) + 273K

So, we are given the following information:

Pressure=760mmHg\\Volume=2.965L\\Temperature=25.5C\°=25.5+273K=298.5K

Now, isolating the number of moles, and substituting the given information, we have:

PV=nRT

n=\frac{PV}{RT}

n=\frac{PV}{RT}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}\\\\n=\frac{2242mmHg.L}{18615.355\frac{mmHg.L}{mol.}}\\\\n=0.120mole

Hence, we have that there were produced 0.120 moles of CO_{2}

n=0.120mol

Have a nice day!

7 0
3 years ago
The properties of the hydrogen atom form the basis for all life. True False
Maurinko [17]
False, the hydrogen atom does not form the basis for all life.
6 0
2 years ago
Read 2 more answers
What is the wavelength of a light of frequency 6.42 x 1014 Hz?
Dahasolnce [82]

Answer:

467 nm is the answer

Explanation:

IT'S the answer for

8 0
3 years ago
Mrs.Jacobs dropped an object from 10 meters she knows it did 50 joules of work how much did it weigh?
Alenkasestr [34]
It is 30 hope it help's.
5 0
3 years ago
A student wants to know why sandhill crane‘s fly south for the winter. The student uses a map of North America to make a model o
Ratling [72]

Answer:

a and c

Explanation:

im probably wrong  though

7 0
3 years ago
Read 2 more answers
Other questions:
  • How many atoms are in 1 mole of hydrogen
    14·1 answer
  • In an endothermic reaction what is true of the enthalpy
    7·1 answer
  • Write the chemical symbol for the isotope of cobalt with 37 neutrons
    13·1 answer
  • Which of these statement(s) is/are true about a balloon filled with 1.00 mol N2 (g) at STP?
    7·2 answers
  • True or False. Physical changes result in the formation of a new substance.
    8·1 answer
  • 100 POINTS!!! ANSWER ASAP
    14·2 answers
  • Please help fast, I will give brainliest!
    7·1 answer
  • Help help help I will give brainliest
    12·2 answers
  • An oil is...<br> a. liquid fat<br> b. solid fat<br> c. gas fat<br> d. slime fat
    8·2 answers
  • The gravitational force exerted by an object is given by F = mg, where F is the force in newtons, m is the mass in kilograms, an
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!