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olya-2409 [2.1K]
2 years ago
13

How does acid base extraction work.

Chemistry
2 answers:
LenKa [72]2 years ago
7 0
Technique. Usually, the mixture is dissolved in a suitable solvent such as dichloromethane or diethyl ether (ether), and poured into a separating funnel. An aqueous solution of the acid or base is added, and the pH of the aqueous phase is adjusted to bring the compound of interest into its required form.
jarptica [38.1K]2 years ago
4 0

Answer:

it can be done using the method of lithium paper

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The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
3 years ago
Which of the following types of electromagnetic waves generally has the least energy
sertanlavr [38]

Radio waves have the lowest energy, but the longest wavelength. So radio waves is the answer. Good luck on the rest and message me for more help.

7 0
3 years ago
Read 2 more answers
PLEASEEE HELPPP!! Due today!!!!
dolphi86 [110]

Answer:

B

Explanation:

A chemical reaction equation is balanced if the number of atoms of each element on the right hand side of the reaction equation is the same as the number of atoms of the same element on the left hand side of the reaction equation.

By inspection, the chemical reaction written in the question is a balanced chemical reaction equation.

However, the statement in option B that more molecules of N2 are needed to produce NH3 than molecules of H2 is a false statement since only one mole of N2 and three moles of H2 are required to produce NH3 according to the reaction equation as written in the question.

3 0
3 years ago
Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus
Oxana [17]

Answer : The mass of chlorine reacted with the phosphorus is, 53.25 grams.

Explanation :

First we have to calculate the moles of phosphorus.

\text{Moles of phosphorus}=\frac{\text{Mass of phosphorus}}{\text{Molar mass of phosphorus}}

\text{Moles of phosphorus}=\frac{15.5g}{31g/mol}=0.5mol

Now we have to calculate the moles of Cl_2

The balanced chemical reaction is:

2P+3Cl_2\rightarrow 2PCl_3

From the balanced chemical reaction, we conclude that

As, 2 moles of phosphorous react with 3 moles of Cl_2

So, 0.5 moles of phosphorous react with \frac{3}{2}\times 0.5=0.75 moles of Cl_2

Now we have to calculate the mass of Cl_2

\text{Mass of }Cl_2=\text{Moles of }Cl_2\times \text{Molar mass of }Cl_2

Molar mass of Cl_2 = 71 g/mol

\text{Mass of }Cl_2=0.75mol\times 71g/mol=53.25g

Therefore, the mass of chlorine reacted with the phosphorus is, 53.25 grams.

4 0
4 years ago
Read 2 more answers
What makes a solution a homogeneous mixture? Question 13 options:
Lesechka [4]
The answer is B. uniform in composition.
5 0
3 years ago
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