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san4es73 [151]
3 years ago
14

To use radioactive dating far a substance you must know the substance

Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
8 0
Your answer would be to know the substance HALF - LIFE.




Hope that helps!!!!
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Which statement is true about the ionic size of the elements in a group as one moves from top to bottom in that group?
nekit [7.7K]

Answer:

Ionic size increases from top to bottom within the group.

Explanation:

  • Ions are formed when neutral atoms of elements gain or lose electron(s).
  • The ionic radius is the distance from the nucleus of an ion to the outermost energy level.
  • The ionic size or radius increases down the group as the number of energy level increases.
  • Therefore, an ion of an element lower in the group will be larger than the ion of an element higher in the group.
  • For example, an ion of potassium, K+, is larger in size compared to the ion of sodium, Na+ since K+ has more energy levels than Na+.
8 0
3 years ago
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A tropical climate is a wet climate. Consider a city like Bogota, Colombia which has a tropical climate. Does a tropical climate
dlinn [17]

Answer:

No, It will mean lot of rains but not every day

Explanation:

In wet tropical climates, the high clouds trap a lot of heat while balancing incoming and outgoing heat energy. When the number of heat trapping cloud remains very low, then the unstable cool air above the clouds cause lot of rain.

Hence, there will rain frequently but no everyday

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3 years ago
The town of Eatonville has decided to replace all of the incandescent light bulbs in their public buildings with more energy-eff
astraxan [27]

Answer:A

Explanation:becuse they waste less heat energy

6 0
2 years ago
Consider the following unbalanced redox reaction:
Olegator [25]
Mn04 is being reduced
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The ccl4 formed in the first step is used as a reactant in the second step. if 2.00 mol of ch4 reacts, what is the total amount
Leni [432]
<span>CH4 + 4 Cl2 → CCl4 + 4 HCl (4.00 mol CH4) x (1/1) x (0.70) = 2.80 mol CCl4 (4.00 mol CH4) x (4/1) x (0.70) = 11.2 mol HCl CCl4 + 2 HF → CCl2F2 + 2 HCl (2.80 mol CCl4) x (2/1) x (0.70) = 3.92 mol HCl 11.2 mol + 3.92 mol = 15.1 mol HCl from both steps</span>
8 0
3 years ago
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