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stich3 [128]
3 years ago
14

Solve each equation

Mathematics
2 answers:
4vir4ik [10]3 years ago
8 0

3b+7-1=-3

3b+6= -3

Move +6 to the other side. Sign changes from +6 to -6.

3b+6-6= -3-6

3b=-9

Divide by 3

3b/3=-9/3

b= -3

3x+1-6x=7

3x-6x+1= 7

-3x+1= 7

Move +1 to the other side. Sign changes from +1 to -1.

-3x+1-1= 7-1

-3x=6

Divide by -3

-3x/3= 6/-3

x= -2

312=-6(7x-3)

Mutiply the bracket by -6

312= (-6)(7x)(-6)(-3)

312= -42x+18

Move +18 to the other side.

312-18= -42x+18-18

312-18= -42x

294=- 42x

divide by -42

294/-42= -42/-42x

x= -7

-4(4n-8)=128

Mutiply the bracket by -4

(-4)(4n)(-4)(-8)= 128

-16n+32= 128

move +32 to the other side

-16n+32-32= 128-32

-16n= 96

divide by -16

-16/-16n= 96/-16

n= -6

Answers:

b= -3

x= -2

x= -7

n= -6

Slav-nsk [51]3 years ago
7 0

Answer:

b= -3

x= -2

x= -7

n = -6

Step-by-step explanation:

3b+7-1=-3

3b = -3 -7 +1

3b = -10+1

3b= -9

b = -9/3

b= -3

3x+1-6x=7

-3x = 7-1

-3x= 6

x= -6/3

x= -2

312=-6(7x-3)

312 = -6*7x +6*3

312= -42x +18

312-18= -42x

294 = -42x

x= -294/42

x= -7

-4(4n-8)=128

-4*4n +4*8 =128

-16n +32 = 128

-16n= 128-32

-16n = 96

n=-96/16

n = -6

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\boxed{\bf \:  \cfrac{13}{5}}

<u>Or in Decimal:</u>

\boxed{\bf \: 2.6}

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<u>Given expression :-</u>

\sf \: ( 26 \div 100) \times 10

<u>Solution :-</u>

\sf  = (26 \div 100 )\times 10

This arithmetic expression may be rewritten as ;

\sf  =  \cfrac{26}{100}  \times 10

Step 1 : <u>Cancel the zero of 10 and one zero of 100</u> :-

\sf  =  \cfrac{26}{10 \cancel0}  \times 1 \cancel0

<em>Results to;</em>

\sf  =  \:  \cfrac{26}{10}  \times 1

\sf  =  \:  \cfrac{26}{10}

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\sf  =  \cfrac{ \cancel{26}}{ \cancel{10}}

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<em>It can also be in Decimal.</em>

That is;

\sf = 2.6

Hence, the answer of the expression would be 13/5 or 2.6 .

\rule{225pt}{2pt}

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