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3 years ago

9

Forces normal to a particle's displacement do no work.

1 answer:

snow_tiger [21]3 years ago

3 0

Answer:

Explanation:

The work done is defined as the product of force applied in the direction of displacement and the displacement.

W = F x d x Cosθ

where, F is the force applied, d be the displacement and θ be the angle between the displacement and force.

For the normal forces, the angle between the displacement and the force applied is 90 degree, and the value of Cos 90 is zero, so the work done is zero.

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2 years ago

A 645-turn coil with a 20.250 m 2 area is spun in Earth’s 5.00×10 −5 T magnetic field, producing a 1.25-V maximum emf. A

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3 years ago

To stop a car, first you require a certain reaction time to begin braking; then the car slows under the constant braking deceler

ANEK [815]

Answer:

a) $t_r = 0.55 s$

b) a = 5.59 m/s²

Explanation:

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total distance traveled by the car to stop is 56.9 m when speed of vehicle is 80 km/h or 80 × 0.278 = 22.24 m/s

total distance traveled by the car to stop is 25.7 m when speed of vehicle is 50.7 km/h or 50.7 × 0.278 = 14.09 m/s

using stopping distance formula

$s_1 = v_1 t_r +\dfrac{v_1^2}{2 a}$ ................(1)

$s_2 = v_2 t_r +\dfrac{v_2^2}{2 a}$ ..............(2)

on solving both the equation we get

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$t_r =\dfrac{22.24^2\times 25.7-14.09^2\times 56.9}{22.4\times 14.09(22.24-14.09)}$

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