All categories

3 years ago

Forces normal to a particle's displacement do no work.

Physics

1 answer:

snow_tiger [21]3 years ago

3 0

Answer:

Explanation:

The work done is defined as the product of force applied in the direction of displacement and the displacement.

W = F x d x Cosθ

where, F is the force applied, d be the displacement and θ be the angle between the displacement and force.

For the normal forces, the angle between the displacement and the force applied is 90 degree, and the value of Cos 90 is zero, so the work done is zero.

You might be interested in

No matter what values of m and k you used for the spring, what is the ratio of the period to k m.

Leto [7]

The relationship between the period of an oscillating spring and the attached mass determines the ratio of the period to $\sqrt{\dfrac{m}{k} }$ .

Response:

The ratio of the period to $\sqrt{\dfrac{m}{k} }$ is always approximately 2·π : 1

<h3>How is the value of the ratio of the period to $\sqrt{\dfrac{m}{k} }$ calculated?</h3>

Given:

The relationship between the period, T, the spring constant k, and the

mass attached to the spring m is presented as follows;

$T = \mathbf{2 \cdot \pi \cdot \sqrt{\dfrac{m}{k} }}$

Therefore, the fraction of of the period to $\sqrt{\dfrac{m}{k} }$ , is given as follows;

$\mathbf{\dfrac{T}{ \sqrt{\dfrac{m}{k} }}} = 2 \cdot \pi$

2·π ≈ 6.23

Therefore;

$T :{ \sqrt{\dfrac{m}{k} }} = 2 \cdot \pi : 1$

Which gives;

The ratio of the period to $\sqrt{\dfrac{m}{k} }$ is always approximately 2·π : 1

Learn more about the oscillations in spring here:

brainly.com/question/14510622

7 0

3 years ago

Explain why it takes much more effort to

natali 33 [55]

Answer:

Mass Kinetic Energy and Jules

Explanation:

The train in question is big and heavy and a car is decently heavy but say a train moving at 55 mph can plow through a car and a car driving at 55mph driving at a train will be stopped dead in its tracks. This is because newtons laws of motion specifically an object in motion will stay in motion unless its opposed. The train also has a payload behind it meaning it hurts with force while a car doesn't have to much mass behind it. The train takes loner to stop for as it's acceleration as well as it's deceleration are very slow because its huge and takes a lot of force to stop it while a car is very centralized and compact when it comes to weight and its brakes are usually effective at stopping at 55 mph in about 2 to 6 seconds while a train might stay moving for a good 35 seconds. The force behind the train is immense for as even if the wheels don't spin at all the train will still move since the force behind it is great and a cars tires have a lot of grip and not a lot mass which plays into the force the car has so it can stop simply.

6 0

3 years ago

A force does work on an object if a component of the force is

IrinaK [193]

Answer:

A force does work on an object if a component of the force is parallel to the displacement of the object.

Explanation:

Work, a measurement of energy is said to be done when a force applied to an object results in the movement of that object to a certain distance and direction. Force is the act of push or pulls occurs on an object as a result of the interaction between that object with another one and displacement is the distance and direction covered by that object as a result of the force applied on it.

The work done (W) by a constant force (F) is equal to the product of the force in the direction of displacement of the object and the distance (d) moved by the object i.e., W = F * d.

The angle between the displacement and the force is θ, then the work done, W = Fd cos θ ........ (1)

Positive work - Force acts in the same direction with respect to the displacement of the object. Here, θ is zero, so cos θ i.e., cos 0 is 1. Therefore, from the equation (1), W = Fd (i.e., work done by the force is positive).

Negative work - Force acts in the opposite direction with respect to the displacement of the object. Here, θ is 180°, so cos θ i.e., cos 180° is -1. Therefore, from the equation (1), W = -Fd (i.e., work done by the force is negative).

If a force is applied to an object and it does not move, then the work done is zero i.e., W = F * 0 = 0. Also, if the force and displacement are at right angle to each other, then θ is 90°. Therefore, from the equation (1), W = 0 since cos 90° is zero.

7 0

4 years ago

A copper wire of length 4.00 cm and radius 4.00 mm has a potential difference of 4.00 nV across the ends of the wire. Calculate

Marrrta [24]

Answer: The amount of charge in microCoulombs is 1.18 ( Q = 1.18µC).

The correct option is 2

Explanation: Please see the attachments below

5 0

3 years ago

Who needs to know physics when they are making a satellite

vladimir2022 [97]

First satellite was Sputnik and it was a race then to send satellites!! Everyone starts experimenting how to launch.

first try was on a dog , Laika !! It was send to space as it is long after sputnik is placed in orbit !!

Now you know everyone knows rocket science and the most active are ISRO (India) and NASA (USA) !!

4 0

4 years ago