3.60 A = 3.60 coulombs of charge per second
(3.60 Coul/sec) x (15.3 sec) = 55.08 coulombs of charge
1 coulomb of charge is carried by 6.25 x 10^18 electrons
Number of electrons =
(55.08 Coul) x (6.25 x 10^18 e/coul) = <em>3.4425 x 10^20 electrons</em>
The magnitude of the electric force on the charge is 5 N.
<h3>Magnitude of force on the charge</h3>
The magnitude of force on the charge is calculated as follows;
F = Eq
where;
- E is electric field
- q is magnitude of the charge
F = 100 N/C x 0.05 C
F = 5 N
Thus, the magnitude of the electric force on the charge is 5 N.
Learn more about electric force here: brainly.com/question/20880591
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Answer:
joules
joules
Explanation:
Let us convert the time in hours into seconds
Change in internal energy
where E is the internal energy in Joules
p is the power in watts
and t is the time in seconds
Joules
Amount of work done by the system
where P is the pressure and V is the volume
Substituting the given values in above equation, we get -
liter-atmospheres
Work done in Joules
Joules
Substituting the given values we get -
Thus
joules
joules
The type of waves used by bats are sound waves. Most of the species use their larynx to produce ultrasound waves in the frequency range of 20 to 200 kilohertz.
These sound waves are echoed, reflected, by surroundings, in this case food or prey. These reflections are received by the specialized receptor cells in the ears of bats. The reflections are analyzed by the brain to make an image.
Fun fact: The brain cells of bats are also specialized to better analyze the frequency of ultrasound used by the bat.
Answer:
If the frequency of the motion of a simple harmonic oscillator is doubled , then maximum speed of the oscillator changes by the factor 2
Explanation:
We know that in a simple harmonic oscillator the maximum speed is given by
= 
Here A is amplitude which is constant , so from above equation we see that maximum speed is directly proportional to 
of the oscillation .
Since 
= 2
Where 
is the maximum speed when frequency is doubled .
