The specific heat of metal is c = 3.433 J/g*⁰C.
<h3>Further explanation</h3>
Given
mass of metal = 68.6 g
t metal = 100 °C
mass water = 84 g
t water = 20 °C
final temperature = 52.1 °C
Required
The specific heat
Solution
Heat can be formulated :
Q = m.c.Δt
Q absorbed by water = Q released by metal
84 x 4.184 x (52.1-20)=68.6 x c x (100-52.1)
11281.738=3285.94 x c
c = 3.433 J/g*⁰C.
Yes you are right .. X is undergoing a change from solid to gas at point E
Use ideal gas law PV=nRT
Convert 5.00 atm to kPa since units must be relative to gas constant (r).
To do this multiply 5 by 101.03 (1 atm=101.3kPa)
Now plug in (506.5kPa)(10.0L)=n(8.31 L•atm/mol•K)(373K)
Solve for n (moles) to get approximately 1.634 mol. Now use dimensional analysis (1.634mol/1)(22.4L/1mol) = 36.6L
no the best source is blood.
The answer would be A will increase and T <span>will decrease.
The product of this reaction emits red light because it absorbs green and blue light. As the reaction occurs, the concentration of the product increase. This will makes absorbance of green and blue light increases and the solution will become redder.</span>
