We have to know the molarity of solution obtained when 5.71 g of Na₂CO₃.10 H₂O is dissolved in water and made up to 250 cm³ solution.
The molarity of solution obtained when 5.71 g of sodium carbonate-10-water (Na₂CO₃.10 H₂O) is dissolved in water and made up to 250.0 cm^3 solutionis: (A) 0.08 mol dm⁻³
The molarit y of solution means the number of moles of solute present in one litre of solution. Here solute is Na₂CO₃.10 H₂O and solvent is water. Volume of solution is 250 cm³.
Molar mass of Na₂CO₃.10 H₂O is 286 grams which means mass of one mole of Na₂CO₃.10 H₂O is 286 grams.
5.71 grams of Na₂CO₃.10 H₂O is equal to
= 0.0199 moles of Na₂CO₃.10 H₂O. So, 0.0199 moles of Na₂CO₃.10 H₂O present in 250 cm³ volume of solution.
Hence, number of moles of Na₂CO₃.10 H₂O present in one litre (equal to 1000 cm³) of solution is
= 0.0796 moles. So, the molarity of the solution is 0.0796 mol/dm³ ≅ 0.08 mol/dm³
I believe 22.4 liters. Hope this helps!
There are 4 lone pairs of electrons present in the carbon dioxide molecule
Answer:
4
Explanation:
cuz i just took a test and the question was this just reversed. if the ph is 4 and the other ph is 100x greater it’s 6. i don’t kno the reasoning lol
<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
To calculate the amount of heat absorbed or released, we use the following equation:
.....(1)
where, q = amount of heat absorbed or released.
m = mass of the substance
c = heat capacity of water = 4.186 J/g ° C
= Change in temperature
We are given:
![m=30g\\\Delta T=[40-0]^oC=40^oC\\q=?J](https://tex.z-dn.net/?f=m%3D30g%5C%5C%5CDelta%20T%3D%5B40-0%5D%5EoC%3D40%5EoC%5C%5Cq%3D%3FJ)
Putting values in equation 1, we get:

q = 5023.2 J
We are given:
![m=40g\\\Delta T=[40-30]^oC=10^oC\\q=?J](https://tex.z-dn.net/?f=m%3D40g%5C%5C%5CDelta%20T%3D%5B40-30%5D%5EoC%3D10%5EoC%5C%5Cq%3D%3FJ)
Putting values in equation 1, we get:

q = 1674.4 J
Heat gained by Trial 1 than trial 2 = 
Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.
Thus, the correct answer is Option b.