Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
Answer:
A carboxyl group (COOH) is a functional group consisting of a carbonyl group (C=O) with a hydroxyl group (O-H) attached to the same carbon atom. Carboxyl groups have the formula -C(=O)OH, usually written as -COOH or CO2H.
Answer:G
Explanation:
I would look it up on safari just to be sure tho, hope this helps
Answer:
The left and right hemispheres of the cerebrum are connected by the Corpus Collosum.
Explanation:
The corpus collosum is a thick band of neurons that divides the cerebral cortex lobes into the left and right hemisphere. The corpus callosum allows for both hemispheres to communicate and transfer information! The primary function of the corpus callosum is to integrate sensory, motor, and cognitive performance between the cerebral cortex.
Ins severe cases of epileptic seizures, a corpus callosotomy is performed, which cuts the corpus callosum in half. This prevents the seizures from becoming more severe, and the brain can reprogram, through neuroplasticity.
