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vladimir1956 [14]
3 years ago
12

Describe the tide requirements necessary to create a tidal power plant.

Physics
1 answer:
spin [16.1K]3 years ago
6 0

Answer:

La energía mareomotriz se produce gracias al movimiento generado por las mareas, esta energía es aprovechada por turbinas, las cuales a su vez mueven la mecánica de un alternador que genera energía eléctrica, finalmente este último esta conectado con una central en tierra que distribuye la energía hacia la comunidad.    

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What is the measure of how much matter is in an object and that can be measured using a balance? a. height b. volume c. weight d
kirill [66]

the answer is D. mass

3 0
3 years ago
Charges of +5C and −9C are at a distance of 1m from each other. Which diagram represents the force between the two charges?
weqwewe [10]

the answer is CCCCCCCCCCCCCCCCC

8 0
4 years ago
Read 2 more answers
A wire with a circular cross section and a resistance R is lengthened to 9.66 times its original length by pulling it through a
damaskus [11]

Answer:

The resistance of the wire after it is stretched is 93.31R.

Explanation:

Resistance is the property of the material to oppose the current flow through it. It is given by the relation :

R = (ρl)/A

Here ρ is resistivity, l is length of wire and A is the area of the wire.

Let l₀, and A₀ are the original length and original circular cross section area of the wire. while l₁ and A₁ are the new length and new circular cross section area of the wire.

Volume of the original wire, V₀ = A₀ x l₀

Volume of the new wire, V₁ = A₁ x l₁

According to the problem. volume remain same. So,

V₀ = V₁

A₀ x l₀ = A₁ x l₁

It is given that l₁ = 9.66 x l₀. Substitute this value in the above equation;

A₀ x l₀ = A₁ x 9.66 x l₀

A₁ = A₀/9.66

Resistance of the original wire, R = (ρl₀)/A₀

Resistance of the new wire, R₁ = (ρl₁)/A₁

Substitute the value of l₁ and A₁ in the above equation.

R₁ = (ρ x l₀ x 9.66)/(A₀/9.66) = 93.31 x (ρl₀)/A₀

But (ρl₀)/A₀ = R. hence,

R₁ = 93.31 R

8 0
3 years ago
A helicopter travels west at 80 mph. It is moving above a car traveling on a highway at 80 mph. Given this information, you can
gavmur [86]

Answer:

d. at the same velocity

Explanation:

I will assume the car is also travelling westward because it was stated that the helicopter was moving above the car. In that case, it depends where the observer is. If the observer is in the car, the helicopter would look like it is standing still ( because both objects have the same velocity). If the observer is on the side of the road, both objects would be travelling at the same velocity. Also recall that, velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes but speed is the rate at which object covers distance and it is not direction wise. Hence velocity is the best option.

5 0
3 years ago
A jet plane is flying at a constant altitude. At time t1 = 0, it has components of velocity vx = 90 m/s, vy = 110 m/s. At time t
Vika [28.1K]

Answer:

a) See attachment.

b) a_avg = -8.66 i - 2.33 j

c) a = 195 degrees from + x-axis.  |a_avg| = 8.97 m/s^2

Explanation:

Given:

- Initial Velocity V_i = (90 i + 110 j)

- Final velocity V_f = (-170 i + 40 j)

- t_i = 0

- t_f = 30.0 s

Find:

(a) Sketch the velocity vectors at t1 and t2. How do these two vectors differ?

(b) the components of the average acceleration

(c) the magnitude and direction of the average acceleration.

Solution:

- The change in velocity is given by:

                            Δ V = (V_f - V_i)

                            Δ V = ( -170 i - 90 i + 40 j - 110 j)

                            Δ V = (-260 i - 70 j)

- The change in time is given as:

                            Δ t = t_f - t_i = 30 - 0 = 30 s

-The average acceleration is:

                            a_avg = Δ V / Δ t

                            a_avg = (-260 i - 70 j) / 30

                           a_avg = -8.66 i - 2.33 j

- The magnitude of acceleration is:

                            |a_avg| = sqrt ( 8.66^2 + 2.33^2)

                            |a_avg| = sqrt (80.4245)

                            |a_avg| = 8.97 m/s^2

- The direction of acceleration is given by:

                            tan (Q) = a_y / a_x

                            Q = arctan(a_y / a_x)

                            Q = arctan(2.33 / 8.66)

                            Q = 15 degrees

Hence, 180 + 15 = a.        a = 195 degrees from + x-axis.

8 0
3 years ago
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