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vladimir1956 [14]
3 years ago
12

Describe the tide requirements necessary to create a tidal power plant.

Physics
1 answer:
spin [16.1K]3 years ago
6 0

Answer:

La energía mareomotriz se produce gracias al movimiento generado por las mareas, esta energía es aprovechada por turbinas, las cuales a su vez mueven la mecánica de un alternador que genera energía eléctrica, finalmente este último esta conectado con una central en tierra que distribuye la energía hacia la comunidad.    

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I HAVE 5 MINUTES!!!!!! A block oscillating on the end of a spring moves from its position of maximum spring stretch to maximum s
Verdich [7]

Therefore, if the block moves from its position of maximum spring stretch to maximum spring compression in 0.25 s, the time required for a full cycle is twice as much; T = 0.5 s.

4 0
3 years ago
How Can the human ear detect the sound
liq [111]

Explanation:

The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear. These bones are called the malleus, incus, and stapes.

8 0
2 years ago
Many biological systems are well-described by the laws of statistical physics. A simple yet often powerful approach is to think
GuDViN [60]

Answer:

z1/z2

Explanation:

we have no quantum effects therefore we can make use of Maxwell Boltzmann distribution in the description of this system.

using the boltzman distribution the probability of finding a particle in energy state

P_{ei}  = \frac{gie^{-ei/kol} }{z}

we have

gi to be degeneration of the ith state

ei to be energy of ith state

z=e^{-ei/kbt} summation

P_{ope} = \frac{e^{-ei/kBt} }{z} = \frac{Z_{1} }{Z}

We have R to be equal to

\frac{P_{ope} }{P_{Close} } = \frac{Z1}{Z2}

8 0
3 years ago
A locomotive accelerates a 25-car train along a level track. Every car has a mass of 7.7 ✕ 104 kg and is subject to a friction f
MaRussiya [10]

To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.

In this way,

The total mass of the cars would be,

m_T = 25(7.7*10^4)Kg

m_T = 1.925*10^6Kg

Therefore the friction force at 29Km / h would be,

f=250v

f= 250*29Km/h

f = 250*29*(\frac{1000m}{1km})(\frac{1h}{3600s})

f = 2013.889N

In this way the tension exerts between first car and locomotive is,

T=m_Ta+f

T=(1.925*10^6)(0.2)+2013.889

T= 3.8701*10^5N

Therefore the tension in the coupling between the car and the locomotive is 3.87*10^5N

6 0
3 years ago
A volumetric flow rate of 2 m^3/ s of liquid water is to be pumped from sea level to an elevation of 1200 m. Taking the density
exis [7]

Answer:

power requirement is 23.52 × 10^{6}  W

Explanation:

given data

flow rate q = 2 m³/s

elevation h = 1200 m

density of the water ρ = 1000 kg/m³

to find out

power requirement

solution

we will get power by the power equation that is

power = ρ× Q× g× h   ...................1

put here all value we get power

power = ρ× Q× g× h

power = 1000 × 2 × 9.8 × 1200

power = 23.52 × 10^{6}

so power requirement is 23.52 × 10^{6}  W

6 0
3 years ago
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