Answer:
v = 27.3 m/s
Explanation:
Given that
Acceleration ,a= 4.2 m/s²
Time ,t= 6.5 s
Lets take the maximum speed gain by Thomson's= v
We know that ,if acceleration is constant then the speed v is given as
v= u + a t
v=final speed
u=initial speed
a=acceleration
t=time
Here the initial speed of Thomson's ,u = 0 m/s
Now by putting the values in the above equation we get
v= 0 + 4.2 x 6.5 m/s
v = 27.3 m/s
Therefore the maximum speed gain by Thomson will be 27.3 m/s.
Answer:
a) Acceleration of the car is given as
b) Acceleration of the truck is given as
Explanation:
As we know that there is no external force in the direction of motion of truck and car
So here we can say that the momentum of the system before and after collision must be conserved
So here we will have
now we have
a) For acceleration of car we know that it is rate of change in velocity of car
so we have
b) For acceleration of truck we will find the rate of change in velocity of the truck
so we have
Answer: (a) 99.5℅ submerged
(B) 96.9℅ submerged
Explanation:
For 995 kilograms per cubic meter, It'll be the 995Kg/m3 density given, divided by the density of fresh water, which is one times ten to the three kilograms per cubic meter, and this works out to 99.5 percent submerged.
If the same person with the same density was floating in salt water, salt water has a slightly higher density of 1027 kilograms per cubic meter, this works out to 96.9 percent submerged.