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RoseWind [281]
2 years ago
8

What is the difference between a free body diagram and a vector diagram?​

Physics
2 answers:
kenny6666 [7]2 years ago
5 0
Free body diagrams are used to describe situations where several forces act on an object. Vector diagrams are used to resolve (break down) a single force into two forces acting at right angles to each other.
Murrr4er [49]2 years ago
4 0

Answer:

Free body diagrams are used to describe situations where several forces act on an object. On the other hand Vector diagrams are used to resolve (break down) a single force into two forces acting as right angles to eachother

Explanation:

Hope this helps !

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IceJOKER [234]
B. Because they are used to see through objects

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3 years ago
Simple curiosity is not a legitimate reason to complete a scientific investigation.
jok3333 [9.3K]
True......I would say...
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Si usted trata de contrabandear lingotes de oro llenando su mochila, cuyas dimensiones son de 56 cm * 28 cm * 22 cm, ¿cuál sería
kati45 [8]

Answer:

Mass, m = 665.77 kg

Explanation:

The question says that "If you try to smuggle gold bars by filling your backpack, whose dimensions are 56 cm * 28 cm * 22 cm, what would be its mass? "

The dimension of gold bar is 56 cm×28 cm×22 cm

We know that the density of gold is 19.3 g/cm³

The mas per unit volume of a material is called its density. It can be given by :

d=\dfrac{m}{V}\\\\m=d\times V\\\\m=(19.3\ g/cm^3)\times (56\times 28\times 22\ cm^3)\\\\m=665772.8\ g\\\\m=665.77\ kg

So, the mass of the gold bar is 665.77 kg.

5 0
3 years ago
g John is walking along a trail when he comes to the bottom of a steep cliff. Before trying to climb up it, he wonders how high
s344n2d4d5 [400]

Answer:

179.655m

Explanation:

Given

Maximum speed of the arrow v = 60m/s

Time taken to hit the top of the cliff t = 7.0s

Required

Height of the cliff H

Using the equation of motion

H = vt + 1/2gt²

Substitute into the formula:

H = 60(7) + 1/2 (-9.81)(7²) (g is negative due to upward motion of the arrow)

H = 420-4.905(49)

H = 420-240.345

H = 179.655m

Hence the cliff is 179.655m high

4 0
3 years ago
(a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 32º ramp at a speed
stiks02 [169]

a) 7 buses

b) 6.8 m

Explanation:

a)

The motion of the motorcycle is a projectile motion, so it consists of 2 independent motions:

- A uniform motion along the horizontal direction

- A uniformly accelerated motion along the vertical direction

The initial components of the velocity of the motorcycle are:

v_x = u cos(32^{\circ})=(40.0)(cos 32^{\circ})=33.9 m/s\\v_y = u sin(32^{\circ})=(40.0)(sin 32^{\circ})=21.2 m/s

The equation for the vertical motion of the motorcycle is

y=h+u_y t - \frac{1}{2}gt^2

where

y is the altitude at time t

h is the initial height

g=9.8 m/s^2 is the acceleration due to gravity

The bus top is at the same height of the initial ramp, so we have

y=h

And therefore, we can solve the equation for t, to find the time of flight:

0=u_y t - \frac{1}{2}gt^2\\t(u_y-\frac{1}{2}gt)=0\\t=\frac{2u_y}{g}=\frac{2(21.2)}{9.8}=4.33 s

Now we find what is the horizontal distance covered by the motorcycle in its jump, which is given by:

d=v_x t = (33.9)(4.33)=146.8 m

And since each bus has a length of L = 20.0 m, the number of buses that the motorcycle can clear with its jump is:

n=\frac{d}{L}=\frac{146.8}{20}=7.34

So, 7 buses.

b)

In the previous problem, we saw that the total range of the motion of the motorcycle is

d=146.8 m

And we said that this corresponds to 7 buses.

Each bus has a length of

L = 20 m

So, the total length of 7 buses is

L' = 7L=7(20)=140 m

Therefore, the range of the motorcycle is greater than the length of the buses by:

\Delta x = d-L'=146.8-140 = 6.8 m

which means he will miss the last bus by 6.8 meters.

6 0
3 years ago
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