Answer:
Because the force one needs to apply is reduced.
Explanation:
- Work can be expressed in terms of force and distance as follows,
Work = Force × distance
- To be more precise, the selection of these two parameters should be in a manner that the distance is what the line of action of the force traces.
- It is obvious that for a given amount of work when one parameter is changed the other changes to counteract the change of the first one.
- Imagine the situation shown in the attached figure. The amount of work that needs to be done during the lifting of the mass to a height of
vertically is 
. - On the slope, however, one needs to push the object an
distance up to get the object to that 
height ultimately. - The work he does on the slope is
and since
, 
. - The force that needs to be applied is less than that applied in the vertical lift. Hence it feels easier. #SPJ4
Answer:
9375 N
Explanation:
From the question,
Centripetal force (F) = mv²/r.................. Equation 1
Where m = mass of the car, v = velocity of the car, r = radius of the curve.
Given: m = 900 kg, r = 600 m, v = 25 m/s
Substitute these values into equation 1
F = (900×25²)/600
F = 9375 N.
Hence the centripetal force on the car is 9375 N
Answer:
The answer is B: to Amplify the sound
Answer:
W = 0 J
Explanation:
The amount of work done by gas at constant pressure is given by the following formula:
where,
W = Work done by the gas
P = Pressure of the gas
ΔV = Change in the volume of the gas
Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:
<u>W = 0 J</u>
Pushing a broke down car, even done by more than one person, is difficult especially if the distance to be covered is quite far. A car is heavy and it requires a lot of force to start the car moving. This is because the inertia of the car to remain at rest is great. Additionally, the force applied in pushing the car must be greater than the frictional force to cause it to accelerate. The frictional force is dependent on the mass of the object which means that the frictional force acting on the car is also great. Finally, with every push of the car, the frictional force will always be present and acting on the opposite direction. The push that will be supplied must be sustained all throughout.
