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lorasvet [3.4K]
2 years ago
13

If a football is thrown from rest with an acceleration of 8.5 m/s2, and had an final

Physics
1 answer:
AnnyKZ [126]2 years ago
4 0

Answer:

t = 2.94 seconds

Explanation:

Given that,

The initial velocity of the football, u = 0

The final velocity of the football, u = 25 m/s

Acceleration, a = 8.5 m/s²

We need to find the time for which the football is accelerating. Let the time is t. We know that,

a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{25-0}{8.5}\\\\t=2.94\ s

So, the football is accelerating for 2.94 seconds.

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Why isn't pluto considered a planet anymore?
aivan3 [116]

The answer is. It did not meet the three criteria the IAU uses to define a full-sized planet.

1. It is in orbit around the Sun

2. It has sufficient mass to assume hydrostatic equilibrium

3. It has 'cleared the neighborhood' around its orbit

Pluto has not 'cleared its neighborhood'

3 0
3 years ago
What type of cooling would a scientist determine formed an igneous rock found with large crystals? Slow cooling Medium rate cool
Dmitriy789 [7]

Slower cooling engenders the growth of larger crystals in igneous rocks, thus, your answer should be slow cooling!

Hope this helped!

5 0
3 years ago
Read 2 more answers
Multiple-Concept Example 9 reviews the concepts that are important in this problem. A drag racer, starting from rest, speeds up
Mademuasel [1]

Answer:

V = 90.51 m/s

Explanation:

From the given information:

Initial speed (u) = 0

Distance (S) = 391 m

Acceleration (a) = 18.9 m/s²

Using the relation for the equation of motion:

v² - u² = 2as

v² - 0² = 2as

v² = 2as

v = \sqrt{2as}

v = \sqrt{2*18.9*391}

v = 121.57 m/s

After the parachute opens:

The initial velocity = 121.57 m/ss

Distance S' = 332 m

Acceleration = -9.92 m/s²

How fast is the racer can be determined by using the relation:

V=  \sqrt{v^2 + 2aS'}

V = \sqrt{121.57^2+ 2 (-9.92)(332)}

V = 90.51 m/s

6 0
3 years ago
t is the estimated distance traveled through the air by a marshmallow that is launched from a 15- cm long launcher when it is pl
DerKrebs [107]

Answer:

10

Explanation:

15 cm minus 5 cm

5 0
3 years ago
If the opening to the harbor acts just like a single-slit which diffracts the ocean waves entering it, what is the largest angle
soldi70 [24.7K]

Answer:

The angle that the wave would be \theta = sin ^{-1}\frac{2 \lambda}{D}

Explanation:

From the question we are told that  the  opening to  the  harbor acts just like a single-slit so a boat in the harbor that at angle equal to the second diffraction minimum would be safe and the  on at angle greater than the diffraction first minimum would be slightly affected

  The minimum is as a result of destructive interference

       And for single-slit this is mathematically represented as

               D sin \ \theta =m \lambda

where D is the slit with

          \theta is the angle relative to the original direction of the wave

         m is the order of the minimum j

        \lambda is the wavelength

Now since in the question we are told to obtain the largest angle at which the boat would be safe

      And the both is safe at the angle equal to the second minimum then

    The the angle is evaluated as

           \theta = sin ^{-1}[\frac{m\lambda}{D} ]

Since for second minimum m= 2

The  equation becomes

               \theta = \frac{2 \lambda}{D}

3 0
3 years ago
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