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USPshnik [31]
3 years ago
9

3m/s for 12 seconds how dar would he walk

Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0
I think 36m/12s because 3×12 =36
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Newton s third law of motion states that every action has an __________ but __________ reaction.
Margaret [11]
Newton´s thrid law of motion states that:
Every action has an equal and opposite reaction.

c. equal, opposite.
3 0
4 years ago
A box has a mass of 35kg.he pulls the rope horizontally with a force of 175 N. Find the horizontal acceleration of the box as it
Cloud [144]

Answer:

3.43 m/s^2

Explanation:

Force is equal to mass times acceleration. (F=ma). You can use inverse operations to get the formula for acceleration, which is acceleration is equal to force divided by mass. (a=F/m). Since there are two forces here, the force friction (55 N), and the force applied (175 N), we must solve for the net force. To solve for the net force, you take the applied force (175 N) and subtract the frictional force from it (55 N). Thus, the net force is 120 N. With this done, we can now solve for our acceleration.

Using the equation for acceleration, we take the force and divide it by mass.

120/35

Answer: 3.43* m/s^2**

*Note: This is rounded to the nearest hundredth, the full answer is: 3.42857143

**Note: In case you're confused, this is meters per second squared.

8 0
3 years ago
A single loop of nickel wire, lying flat in a plane, has an area of 7.40 cm^2 and a resistance of 2.40 Ω. A uniform magnetic fie
ale4655 [162]

Explanation:

It is given that,

Area of nickel wire, A=7.4\ cm^2=7.4\times 10^{-4}\ m^2

Resistance of the wire, R = 2.4 ohms

Initial value of magnetic field, B_1=0.5\ T

Final magnetic field, B_2=3\ T

Time, t = 1.12 s

Let I is the induced current in the loop of wire over this time. Te emf induced in the wire is given by Faraday's law as :

\epsilon=-\dfrac{d\phi}{dt}

\epsilon=-\dfrac{d(BA)}{dt}

\epsilon=-A\dfrac{d(B)}{dt}

\epsilon=-A\dfrac{B_2-B_1}{t}

\epsilon=-7.4\times 10^{-4}\times \dfrac{3-0.5}{1.12}

\epsilon=1.65\times 10^{-3}\ V

Induced current in the loop of wire is given by :

I=\dfrac{\epsilon}{R}

I=\dfrac{1.65\times 10^{-3}}{2.4}

I=6.87\times 10^{-4}\ A

So, the induced current in the loop of wire over this time is 6.87\times 10^{-4}\ A. Hence, this is the required solution.

7 0
3 years ago
Which of the following statements are true?
ale4655 [162]

Answer:

A) True. Voltmeters measure voltages

C) True. They are placed in parallel

E) True ammeters are used to measure current

Explanation:

The devices for voltage measurement are the voltmeter and ammeter

Voltmeters have very high intense resistance and are placed in parallel

The ammeters have very small resist and are placed in series

Based on this establishment, let's analyze the statements

A) True. Voltmeters measure voltages

B) False has high intense resistance

C) True. They are placed in parallel

D) False ammeters are placed in series

E) True ammeters are used to measure current

F) False ammeters have a low internal resistance

4 0
3 years ago
Read 2 more answers
A moving roller coaster speeds up with constant acceleration for 2.3\,\text{s}2.3s2, point, 3, start text, s, end text until it
Ad libitum [116K]

Answer:

Δx=(v+v0/2)t

Explanation:

We can figure out which kinematic formula to use by choosing the formula that includes the known variables, plus the target unknown.

In this problem, the target unknown is the initial velocity v_0v  

0

​  

v, start subscript, 0, end subscript of the roller coaster.

7 0
3 years ago
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