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3 years ago

3m/s for 12 seconds how dar would he walk

Physics

1 answer:

Sunny_sXe [5.5K]3 years ago

4 0

I think 36m/12s because 3×12 =36

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What is first and second conditions of equilibrium?

sdas [7]

I think the answer is the first condition sum of forces acting on a body is zero ( ∑ F =0 ) and the second condition sum of torque acting on a body is ( ∑ τ = 0 )

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2 years ago

Light of wavelength 480 nm illuminates a double slit, and the interference pattern is observed on a screen. At the position of t

vova2212 [387]

Answer:

BC =980nm

Explanation:

Given wavelength =490nm

m=2

Required to find (OB - OC) = BC (more distant slit - nearest slit ) = dsin theta

We have dsin theta = m*wavelength

or BC = m* wavelength = 2*490nm

= 980nm = 98.000A

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2 years ago

An electric filament lamp is connected to a power supply and switched on.

ladessa [460]

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2 years ago

A dogs tail hit a 1.3kg flower vase, knocking it over. the net force on the flower vase over time is shown below

lesantik [10]

Answer: 0.15 m/s

Explanation:

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2 years ago

A bowling ball with a momentum of 18kg-m/s strikes a stationary bowling pin. After the collision, the ball has a momentum of 13k

Veronika [31]

Answer:

$14.98\ \text{kg m/s}$

$45.26^{\circ}$

Explanation:

$P_1$ = Initial momentum of the pin = 13 kg m/s

$P_i$ = Initial momentum of the ball = 18 kg m/s

$P_2$ = Momentum of the ball after hit

$55^{\circ}$ = Angle ball makes with the horizontal after hitting the pin

$\theta$ = Angle the pin makes with the horizotal after getting hit by the ball

Momentum in the x direction

$P_i=P_1\cos55^{\circ}+P_2\cos\theta\\\Rightarrow P_2\cos\theta=P_i-P_1\cos55^{\circ}\\\Rightarrow P_2\cos\theta=18-13\cos55^{\circ}\\\Rightarrow P_2\cos\theta=10.54\ \text{kg m/s}$

Momentum in the y direction

$P_1\sin55=P_2\sin\theta\\\Rightarrow P_2\sin\theta=13\sin55^{\circ}\\\Rightarrow P_2\sin\theta=10.64\ \text{kg m/s}$

$(P_2\cos\theta)^2+(P_2\sin\theta)^2=P_2^2\\\Rightarrow P_2=\sqrt{10.54^2+10.64^2}\\\Rightarrow P_2=14.98\ \text{kg m/s}$

The pin's resultant velocity is $14.98\ \text{kg m/s}$

$P_2\sin\theta=10.64\\\Rightarrow \theta=sin^{-1}\dfrac{10.64}{14.98}\\\Rightarrow \theta=45.26^{\circ}$

The pin's resultant direction is $45.26^{\circ}$ below the horizontal or to the right.

4 0

2 years ago